JHTUREIWKMFDNGWEIJQOLSDM,FNMGBTJIHRENKDBVAlnakbsjdgvutrfeihwojdaslzbcdvjrdgueDKSJHGCNADFLIGA.lsvjzbdugikzhdlvx,mglhzfkvbcnjugbdfnvfbhghiszkjmnvfbhgraihedsknczvbhfgfvbxcdnsakwdeursgvxftfvrdzjxnbcdhgyrujsdnbgdhjsbdfgyduksjnxbvcfgyudksmznbshdeuifknjdhgdfhskjzknbgjdkfhsnbsjgfsh. SOOOOOOO, thats the answer. :)))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))
It is: 3p+5p = 8p
-8p + 3 = -29 8p - 3 = 29 8p = 29 + 3 8p = 32 p = 32/8 p = 4
8p = 3p + 25 Subtract 3p from both sides: 5p = 25 Divide both sides by 5: p = 5
-8 = -8p + 4Add 8p to each side:8p - 8 = 4Add 8 to each side:8p = 12Divide each side by 8:p = 1.5
20p - 8p = 12p
To find the value of ( 3p^2 - 8p + 4 ), you simply substitute the value of ( p ) into the expression. If ( p ) is a specific number or variable, plug it into the equation. For example, if ( p = 2 ): [ 3p^2 - 8p + 4 = 3(2)^2 - 8(2) + 4 ] [ = 3 \cdot 4 - 16 + 4 ] [ = 12 - 16 + 4 ] [ = 0 ] Therefore, when ( p = 2 ), ( 3p^2 - 8p + 4 = 0 ). If ( p ) is a variable and not a specific number, the expression ( 3p^2 - 8p + 4 ) represents a quadratic polynomial that can be factored or evaluated depending on the context or requirements of the problem.
#include<stdio.h> #include<conio.h> void main() { clrscr(); int i; int a[4]={1,2,3,4}; int *p1,*p2,*p3; for(i=0;i<4;i++) { p1=&a[0]; p2=&a[2]; p3=*p2-*p1; printf("\n value of p3%d",p3); } getch(); }
8p+5 = 11+7p= 8p-7p = 11-5p = 6
We can not provide a specific value as an answer to this question as both p and q are variables and their value is unspecified.However we can write this as:-8(p + q).We can multiply out the bracket to get:-8p + -8q.This is as far as we can answer this question unless the values of p and q are known.-8(p + q) = -8p + -8q
Please help, math problems. 8p - 10 of 5 + x = ...??
8p-p-4p= 7p-4p= 3p
Yes -------------------------- 8p is equivelant to 8 1 pennies.