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Its value is 1 when the statement is true and 0 otherwise.

Its value is 1 when the statement is true and 0 otherwise.

Its value is 1 when the statement is true and 0 otherwise.

Its value is 1 when the statement is true and 0 otherwise.

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Its value is 1 when the statement is true and 0 otherwise.

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Q: What is the value of 8s minus 8 equals 64?
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Related questions

How many 8s are there in 64?

64 = 8 x 8 !


What is the value of s in the equation 4(2s minus 1) equals 7s plus 12?

You said that 4(2s - 1) = 7s + 12Eliminate parentheses: 8s - 4 = 7s + 12Add 4 to each side: 8s = 7s + 16Subtract 7s from each side: s = 16


What is 5 8s of 64 km?

5/8 of 64 km = 40 km


Solve the following equation for s 8s equals p?

8s=ps=p/8


What is 8s equals 72?

8s = 72 divide both sides by 8 s = 9


When a number is increased by 8 the original value is 75 percent of the new value What is the original value of the number?

So 25% of the new value is the newly-added 8. Therefore the original value is three times that, i.e. 24. This means that three 8s plus the other 8 - i.e. four 8s - equals 32.


Is 7 and 8s the greatest value out of 3 and 5?

No, because 7 and 8s is not a value out of 3 and 5 in the first place!if you mean 7/8 and 3/5 then the greatest value is 7/8


Solve the system of equations 3r -4s equals 0 and 2r plus 5s equals 23?

Presumably this is a simultaneous equation in the form of: 3r-4s = 0 2r+5s = 23 Multiply all the terms in the top equation by 2 and in the bottom equation by 3: 6r-8s = 0 6r+15s = 69 Subtract the bottom equation from the top equation: -23s = -69 Divide both sides by -23 to find the value of s remembering that a minus number divided into a minus number is equal to a plus number: s = 3 Substitute the value of s into the original equations to find the value of r: Therefore: r = 4 and s = 3


When each side of a given square is increace by 4 feet the area is increaced by 64 square feet determine the dimensions of the original square?

The original square was 6 ft along each side. Let s be the side of the original square, then: Area_square = s x s = s2 Area_new_square = (s + 4) x (s + 4) = s2 + 8s + 16 But: Area_new_square = Area_square + 64 => s2 + 8s + 16 = s2 + 64 => 8s = 48 => s = 6


How many 8s go into 65?

65 divided by 8 equals 8 with a remainder of 1.


How do you do the addition elimination method on this 4s minus 5t equals 18 and 6s plus 10t equals -8?

4s-5t = 18 6s+10t = -8 Multiply all the terms in the top equation by 2: 8s-10t = 36 6s+10t = -8 Adding both equations leaves you with: 14s = 28 Divide both sides of the equation by 14 to find the value of s: s = 2 Substitute the value of s into the original equations to find the value of t: t = -2 Remember when substituting that a - times a - is equal to a + therfore: -5t = 10


What is 64 divided by 8?

8