Presumably this is a simultaneous equation in the form of:
3r-4s = 0
2r+5s = 23
Multiply all the terms in the top equation by 2 and in the bottom equation by 3:
6r-8s = 0
6r+15s = 69
Subtract the bottom equation from the top equation:
-23s = -69
Divide both sides by -23 to find the value of s remembering that a minus number divided into a minus number is equal to a plus number:
s = 3
Substitute the value of s into the original equations to find the value of r:
Therefore: r = 4 and s = 3
16
(2,3)
The solutions are: x = -2 and y = 4
You cannot solve 1 linear equation in 2 unknown variables. You need at least two independent equations.
{-1,-2}
x = 4 and y = 0
the answer
x = -1.2, y = -3
a=5: c=4
Solve this system of equations. 5x+3y+z=-29 x-3y+2z=23 14x-2y+3z=-18 Write the solution as an ordered triple.
To solve for two unknowns (x and y) it is necessary to have two independent equations.
x = 6 and y = -2
(0,7)
To solve an equation with three unknowns, x, y and z, you require 3 independent equations.
16
When talking about a "system of equations", you would normally expect to have two or more equations. It is quite common to have as many equations as you have variables, so in this case you should have two equations.
(2,3)