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Solve the system of equations 3r -4s equals 0 and 2r plus 5s equals 23?
Wiki User
∙ 14y ago
Presumably this is a simultaneous equation in the form of:
3r-4s = 0
2r+5s = 23
Multiply all the terms in the top equation by 2 and in the bottom equation by 3:
6r-8s = 0
6r+15s = 69
Subtract the bottom equation from the top equation:
-23s = -69
Divide both sides by -23 to find the value of s remembering that a minus number divided into a minus number is equal to a plus number:
s = 3
Substitute the value of s into the original equations to find the value of r:
Therefore: r = 4 and s = 3
Wiki User
∙ 14y ago
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