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Sin (2π/3) =√3/2
Cos (2π/3) =-0.5
Since Tan = Sin/Cos
Tan (2π/3) = (√3/2)/(-0.5) = -√3
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What is the exact value of tan pie over 6?
1/sqrt(3)
What is the absolute value of negative 2 over 3?
I believe that the answer is 2 over 3
If tan is square root of 3 what is cos?
tan θ = √3. tan-1(√3) = π/3 radians or 4π/3 radians, in degrees it would be 60° or 240° tan θ = sin θ / cos θ So, tan (π/3) = sin (π/3) / cos (π/3) = tan (4π/3) = sin (4π/3) / cos (4π/3) cos (π/3) = 1/2 cos (4π/3) = -1/2 Therefore cos θ = 1/2 or -1/2 when tan θ = √3
What is the value of 3 1 over 12 - 2 over 3?
3 1/12 - 2/3 = 2 13/12 - 8/12 = 2 5/12
What is 1 over 2 to 3 over 4 in percent?
Change the 1/2 to 2/4 so you have 2/4 to 3/4 (same denominator) Divide old value by new value to find the difference 2 - 3 = 1 difference Divide difference by old value 1 / 2 = 0.5 Times by 100 = 50 So the increase is 50%
What is the exact value of tan pie over 3?
tan(pi/3)= sqrt(3)
What is the exact value of tan pie over 6?
1/sqrt(3)
What is the exact value of tan 105 degrees?
To find the exact value of tan 105°. First, of all, we note that sin 105° = cos 15°; and cos 105° = -sin 15°. Thus, tan 105° = -cot 15° = -1 / tan 15°. Using the formula tan(α - β) = (tan α - tan β) / (1 + tan α tan β); and using, also, the familiar values tan 45° = 1, and tan 30° = ½ / (½√3) = 1/√3 = ⅓√3; we have, tan 15° = (1 - ⅓√3) / (1 + ⅓√3); whence, cot 15° = (1 + ⅓√3) / (1 - ⅓√3) = (√3 + 1) / (√3 - 1) {multiplying through by √3} = (√3 + 1)2 / (√3 + 1)(√3 - 1) = (3 + 2√3 + 1) / (3 - 1) = (4 + 2√3) / 2 = 2 + √3. Therefore, tan 105° = -cot 15° = -2 - √3, which is the result we sought. We are asked the exact value of tan 105°, which we gave above. We can test the above result to 9 decimal places, say, by means of a calculator: -2 - √3 = -3.732050808; and tan 105° = -3.732050808; thus indicating that we have probably got the right result.
What is the exact value of tan -60?
tan(-60 degrees) = - sqrt(3)
What is the exact trigonometric function value of cot 15 degrees?
cot(15)=1/tan(15) Let us find tan(15) tan(15)=tan(45-30) tan(a-b) = (tan(a)-tan(b))/(1+tan(a)tan(b)) tan(45-30)= (tan(45)-tan(30))/(1+tan(45)tan(30)) substitute tan(45)=1 and tan(30)=1/√3 into the equation. tan(45-30) = (1- 1/√3) / (1+1/√3) =(√3-1)/(√3+1) The exact value of cot(15) is the reciprocal of the above which is: (√3+1) /(√3-1)
What is the absolute value of negative 2 over 3?
I believe that the answer is 2 over 3
Which is greater tan 1tan2 tan3 .arrange them in descending order?
If the angles are measured in degrees or gradians, then: tan 3 > tan 2 > tan 1 If the angles are measured in radians, then: tan 1 > tan 3 > tan 2.
What is the absolute value of 2 over 3 in fractions?
2/3
What is the value of 3 over 2?
1.5
If tan is square root of 3 what is cos?
tan θ = √3. tan-1(√3) = π/3 radians or 4π/3 radians, in degrees it would be 60° or 240° tan θ = sin θ / cos θ So, tan (π/3) = sin (π/3) / cos (π/3) = tan (4π/3) = sin (4π/3) / cos (4π/3) cos (π/3) = 1/2 cos (4π/3) = -1/2 Therefore cos θ = 1/2 or -1/2 when tan θ = √3
What are the polar coordinates?
What are polar coordinates of (√2, 1)? Solution: Here we need to convert from rectangular coordinates to polar coordinates: P = (x, y) = (r, θ) r = ± √(x^2 + y^2); tan θ = y/x or θ = arc tan (y/x) So we have: P = (√2, 1) r = ± √[(√2)^2 + 1^2] = ± √3 θ = arc tan (y/x) = arc tan (1/√2) = arc tan (√2/2) ≈ 35.3°, which is one possible value of the angle. (√2, 1) is in the Quadrant I. If θ = 35.3°, then the point is in the terminal ray, and so r = √3. Therefore polar coordinates are (√3, 35.3°). Another possible pair of polar coordinates of the same point is (-√3, 215.3°) (180° + 35.3° = 215.3°). Edit: Note the negative in the r value.
What is the value of 3 1 over 12 - 2 over 3?
3 1/12 - 2/3 = 2 13/12 - 8/12 = 2 5/12
