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The cosine rules for a triangle ABC with sides a (opposite angle A), b (opposite angle B) and c (opposite angle C) states:

a² = b² + c² - 2bc cos A

Here:

A = 60°

a = X - 3 cm

b = 15 cm

c = X cm

(the assignment of b and c doesn't matter as they can be interchanged in the rule)

→ (X - 3)² = 15² + X² - 2 × 15 × X × cos 60°

→ X² - 6X + 9 = 225 + X² - 15X × 2 × ½

→ -6X + 9 = 225 -15X

→ 9X = 216

→ X = 24

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Q: What is the value of X when a triangle has sides of 15cm by Xcm by X-3cm which is opposite to an angle of 60 degrees?
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