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There are no operator symbols before 5, before log 10 and before 4.
12/4=3 3 is not a value of 5
The absolute value of - 4 5/6 is 4 5/6.
The value of 5 to the negative 4th power (5-4) is 0.0016
It is 5/4
4/5X4= 4/20=1/5=0.2
The KB value is listed below: pKa + pKb - 14 pKa = -log10 (Ka), Ka of acetic acid = 1.8*10^-5 pKa = 4.74, pkb = 9.255 9.255 = -log10(Kb), Kb = 5.56*10^-10
Unfortunately, limitations of the browser used by Answers.com means that we cannot see most symbols. It is therefore impossible to give a proper answer to your question. Please resubmit your question spelling out the symbols as "plus", "minus", "equals".
12/4=3 3 is not a value of 5
(4)5 = 1,024
The pH of a solution is defined as -log10[H+]. Thus a solution with a hydrogen ion concentration of 10-5M has a pH of 5. [H+] = 10-5 pH = -log[H+] pH = - log [10-5] pH = 5
4 and 5/6
The solution to this problem is simple if you just work backwards. pH= -log10[H+] You already know what your pH is, so write your equation like this: 4.3= -log10[H+] An understanding of basic logarithm properties lets you know that you can rewrite the equation like this: 10-4.3= [H+] 5.0 *10-5 = [H+]
The absolute value of - 4 5/6 is 4 5/6.
The value of 5 to the negative 4th power (5-4) is 0.0016
It is 5/4
4/5X4= 4/20=1/5=0.2
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