With out an equality sign the given expression can't be considered to be an equation and so therefore no solution is possible.
12h-17-h+16-2h =12h-3h-17+16 =9h-1,if you mean the value of h,then h =1/9
It is: 11h
8
Carbonic acid, H2CO3
H is 30
2H+ + SO42- + Ca2+ + 2I- CaSO4 + 2H+ + 2I-
2h + 2h + 2h = 6h
2H+ + SO42- + Ca2+ + 21 > CaSO4 + 2H+ + 21-
Cl2 + 2H = 2HCl
This is a net ionic equation from a double replacement reaction. There should have been 2H+, otherwise the equation doesn't balance. 2H+ + 2CrO42- --> Cr2O72- + H2O
The net ionic equation is SO42- + Ca2+ CaSO4.
The net ionic equation is SO42- + Ca2+ CaSO4.
First set up the equation: 2h+10=40 Then get the variable alone by subtracting 10 from each side: 2h=30 And continue by dividing both sides by two 2h=30 ______ 2 2 h=15 So your answer is h=15
- 3h - 2h + 6h + 9 = h + 9
FeS + 2H+ -> Fe2+ + H2S
2H+ + SO42- + Ca2+ + 2I- CaSO4 + 2H+ + 2I
Ca2+(aq) + SO42-(aq)- --> CaSO4(s) is the net ionic equation.