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The value is 1 if (x, y) = (4, 3) and 0 otherwise.

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Q: What is the value of the expression x equals 4 and y equals 3?
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What is the value of the expression r2 plus s3 when are equals 2 and s equals 3?

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what is the value when (n-2)^2+n-1when n=4?

To find the value of (n-2)^2 + n-1 when n=4, we simply substitute 4 for n in the expression: (n-2)^2 + n-1 When we do this, the expression becomes: (4-2)^2 + 4-1 Now we need to simplify the expression within the parentheses first. The expression within the parentheses is (4-2)^2, which means we need to subtract 2 from 4 and then square the result. So, we get: 2^2 Which equals 4. Now we can substitute this value back into the original expression to get: 4 + 4-1 Next, we simplify the expression 4-1, which equals 3. So, the expression becomes: 4 + 3 And we can simplify that further to get: 7 So, when n=4, the value of (n-2)^2 + n-1 is 7


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