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What is the value of x in the equation 6x squared plus 2x plus k equals 0 showing work as well as an answer?
Wiki User
∙ 8y ago
Using the quadratic formula, you will find for the equation 6x² + 2x + k = 0:
x = (-b ±√(b² - 4ac)) / 2a
→ x = (-2 ± √(2² - 4×6×k)) / (2×6)
→ x = (-2 ± √(4 - 4×6k)) / (2×6)
→ x = (-1 ± √(1 - 6k)) / 6
The value of the discriminant (b² - 4ac) affects the value of x:
>0 → there are two real values of x; this happens when 1 - 6k > 0 → k < 1/6;
=0 → there is one repeated root, ie a single value of x; this happens when k = 1/6 (making x = -1/6);
<0 → there are two complex values of x; this happens when k > 1/6.
Wiki User
∙ 8y ago
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