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E = I R = (2) (6) = 12 volts
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∙ 12y ago
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What would the voltage be in a DC circuit if there were a current flow of 6 A and a resistance of 8 ohms?
Ohms Law! E=IR Voltage equals current times resistance. Get out the old calculator...
How much voltage is needed to produce a current of 2 ampsthrough a resistance of 6 ohms?
12 voltage
What is the current when the voltage is 18 volts and the resistance is 6 ohms?
V=i*r=2*6=12v
What is the voltage drop through a resistor of 6 ohms (2 amps)?
12 volts
If the voltage is 90 and the resistance is 6 ohms what is the current flow?
0.5amp
What is the difference between 6 ohms and 8 ohms?
Though it is tempting to say the difference is 2 ohms (8 ohms minus 2 ohms equals 6 ohms), lets look at some things. The 6 ohms is 3/4ths the resistance of the 8 ohms. If the resistances are loads, the 6 ohm load will draw 1/3rd more current than the 8 ohm load. The 8 ohm load will draw 3/4ths as much as the 6 ohm load. Those are some differences between 6 ohms and 8 ohms.
What voltage is needed to produce a current of 2 amps through a resistance of 6 ohms?
Where: V = Voltage (Volts), A = Current (Amps) and R = Resistance, (Ohms)Here are a few easy and related equations.V = A * RR= V / AA = V / RSo we have R=3 and A =6 and using the V=A*R equation we getVolts = A(6)*R(3) = 18 Volts.
Three resistors R1 2 R2 4 and R3 6 are connected in series to a battery of 36 V The total resistance in the circuit is?
Resistors placed in series create a total resistance that is found by simply adding the values of the resistors. (Knowing the applied voltage isn't necessary to solve this problem.) Rt = R1 + R2 + R3 = 2 ohms + 4 ohms + 6 ohms = 12 ohms
What is the current in a parallel circuit which has two resistors (17.2 ohms and 22.4 ohms) and a power source of 6.0 volts?
By Ohm's Law, current is voltage divided by resistance, so a voltage of 6 volts across a resistance of 24 ohms will develop a current of 0.25 amperes.
What is the total resistance of a 6-ohm resistor and a 12-ohm resistor in a parallel series?
In series like so ---6 ohms ---- 12 ohms --- , the total resistance is just 6 ohms + 12 ohms.assuming you mean in parallel like this:_|---6 ohms-----|-|~|-_|---12 ohms---|then the resistance of this can be calculated like so:1/6 ohms + 1/12 ohms = 1/R (where R is the resistance of the circuit as a whole)2/12 ohms + 1/12 ohms = 1/R3/12 ohms = 1/R1/4 ohms = 1/Rso R = 4 ohmsA few notes, if the resistors are in parallel the total resistance will always be less than or equal to the lowest resistance in parallel (i.e 6 ohms in parallel with 12 ohms will have resistance less than 6 ohms).Also if two resistances in parallel are the same, then the resistance is half of the resistance of both resistors (i.e. 1/2 ohms + 1/2 ohms = 1/R; 1 = 1/R, R=1 ohm which is half of 2 ohms).This process can be extended to 2 or more resistors in parallel.i.e if we had a 6 ohm, 6 ohm and 12 ohm resistor in parallel we could go1/6 ohms + 1/6 ohms + 1/12 ohms = 1/R(1/6 ohms + 1/6 ohms) + 1/12 ohms = 1/R1/3 ohms + 1/12 ohms = 1/R4/12ohms + 1/12 ohms = 1/R5/12 ohms = 1/Rso R = 12/5 ohms or 2.4 ohms
What is the resistance of the circuit if current flow is 6 amperes in a 120-V circuit?
Google Ohms Law. It will give you all the formulas you need to compute Ohms,Volts and Amps. Simple formulas :-)
If the voltage is 12 volts and the resistance is 3 ohms what are the amps in this circuit?
Using Ohm's law, we can find the current (I) in a circuit where 3 ohms is the resistance (R) and 12 volts is the appllied voltage (V). [(E) means energy]I = V / R = 12 / 3 = 4 amps.Visit this link http://www.csgnetwork.com/ohmslaw2.html for making Ohm's Law calculations.
