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E = I R = (2) (6) = 12 volts

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14y ago

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What would the voltage be in a DC circuit if there were a current flow of 6 A and a resistance of 8 ohms?

Ohms Law! E=IR Voltage equals current times resistance. Get out the old calculator...


How much voltage is needed to produce a current of 2 ampsthrough a resistance of 6 ohms?

12 voltage


What is the current when the voltage is 18 volts and the resistance is 6 ohms?

V=i*r=2*6=12v


What is the voltage drop through a resistor of 6 ohms (2 amps)?

12 volts


If the voltage is 90 and the resistance is 6 ohms what is the current flow?

0.5amp


What is the difference between 6 ohms and 8 ohms?

Though it is tempting to say the difference is 2 ohms (8 ohms minus 2 ohms equals 6 ohms), lets look at some things. The 6 ohms is 3/4ths the resistance of the 8 ohms. If the resistances are loads, the 6 ohm load will draw 1/3rd more current than the 8 ohm load. The 8 ohm load will draw 3/4ths as much as the 6 ohm load. Those are some differences between 6 ohms and 8 ohms.


What voltage is needed to produce a current of 2 amps through a resistance of 6 ohms?

Where: V = Voltage (Volts), A = Current (Amps) and R = Resistance, (Ohms)Here are a few easy and related equations.V = A * RR= V / AA = V / RSo we have R=3 and A =6 and using the V=A*R equation we getVolts = A(6)*R(3) = 18 Volts.


Three resistors R1 2 R2 4 and R3 6 are connected in series to a battery of 36 V The total resistance in the circuit is?

Resistors placed in series create a total resistance that is found by simply adding the values of the resistors. (Knowing the applied voltage isn't necessary to solve this problem.) Rt = R1 + R2 + R3 = 2 ohms + 4 ohms + 6 ohms = 12 ohms


What is the current in a parallel circuit which has two resistors (17.2 ohms and 22.4 ohms) and a power source of 6.0 volts?

By Ohm's Law, current is voltage divided by resistance, so a voltage of 6 volts across a resistance of 24 ohms will develop a current of 0.25 amperes.


What is the total resistance of a 6-ohm resistor and a 12-ohm resistor in a parallel series?

In series like so ---6 ohms ---- 12 ohms --- , the total resistance is just 6 ohms + 12 ohms.assuming you mean in parallel like this:_|---6 ohms-----|-|~|-_|---12 ohms---|then the resistance of this can be calculated like so:1/6 ohms + 1/12 ohms = 1/R (where R is the resistance of the circuit as a whole)2/12 ohms + 1/12 ohms = 1/R3/12 ohms = 1/R1/4 ohms = 1/Rso R = 4 ohmsA few notes, if the resistors are in parallel the total resistance will always be less than or equal to the lowest resistance in parallel (i.e 6 ohms in parallel with 12 ohms will have resistance less than 6 ohms).Also if two resistances in parallel are the same, then the resistance is half of the resistance of both resistors (i.e. 1/2 ohms + 1/2 ohms = 1/R; 1 = 1/R, R=1 ohm which is half of 2 ohms).This process can be extended to 2 or more resistors in parallel.i.e if we had a 6 ohm, 6 ohm and 12 ohm resistor in parallel we could go1/6 ohms + 1/6 ohms + 1/12 ohms = 1/R(1/6 ohms + 1/6 ohms) + 1/12 ohms = 1/R1/3 ohms + 1/12 ohms = 1/R4/12ohms + 1/12 ohms = 1/R5/12 ohms = 1/Rso R = 12/5 ohms or 2.4 ohms


What is the resistance of the circuit if current flow is 6 amperes in a 120-V circuit?

Google Ohms Law. It will give you all the formulas you need to compute Ohms,Volts and Amps. Simple formulas :-)


If the voltage is 12 volts and the resistance is 3 ohms what are the amps in this circuit?

Oh, dude, it's like basic math here. So, you just divide the voltage by the resistance to get the current. In this case, 12 volts divided by 3 ohms equals 4 amps. So, the current in this circuit would be 4 amps. Easy peasy lemon squeezy!