V = 169.65 m3
6m + 5n - 4m + 7n = 2m + 12n
1m and 11m 2m and 10m 3m and 9m 4m and 8m 5m and 7m. The next one, 6m and 6m, would be a square.
6m + 5 = 3m - 4Subtract 3m from each side:3m + 5 = -4Subtract 5 from each side:3m = -9Divide each side by 3:m = -3
4m + 3m = 180 7m = 180 m = 25 5/7
-15m but -15 metres doesnt exist
2 - 3m + 7 = 4m - 9 - m - 28 46 = 6m 46/6 = 23/3 = 7.6666 = m
To calculate the volume of air that can enclose the tent, you would use the formula for the volume of a rectangular prism, which is length x width x height. In this case, the length is 6m, the width is 6m, and the height is 4m. Therefore, the volume of air that can enclose the tent would be 6m x 4m x 4m = 96 cubic meters.
V = 169.65 m3
use the net to find the lateral area of the prism 3m 6m 3m 6m 15m
5*4*3 60?
4m - 8 = 6m =>4m - 6m = 8 => -2m = 8 => m = -(8/2) => m = -4
6m + 5n - 4m + 7n = 2m + 12n
6m + 7 - 2m + 1 = 4m + 8 If you meant: (6m + 7) - (2m + 1) = 4m + 6
-3
1m and 11m 2m and 10m 3m and 9m 4m and 8m 5m and 7m. The next one, 6m and 6m, would be a square.
The value of m in the equation: 4m-5 = 3m +7 is 12.