56.54866776 or 56.55 cubic meters to 2 d.p.
150.796 m2 (rounded)
A cone is one third of the volume of the cylinder of the same base. Since a cylinder has a volume of pi x radius2 x height, the radius being 5.25m and the height being 3m, the volume of the corresponding cone would be 259.7704425m3.The surface area of the top of the cone is defined as pi x radius x slant height. The slant height, by pythagoras, is 6.046693311m, and so the area of the canvas required to cover the heap would be 99.73029825m2.
A rectangular prism with a length of 11m, width of 8m and height of 3m has a volume of 264m3
Radius: 3/2 = 1.5m
339.29 m3 to two decimal places.
56.54866776 or 56.55 cubic meters to 2 d.p.
150.796 m2 (rounded)
V = 141.37 m3
To calculate the volume of a cylinder, use the formula V = πr^2h, where r is the radius and h is the height. Given a diameter of 0.75 (which is equivalent to a radius of 0.375) and a height of 3m, the volume would be π(0.375)^2(3) ≈ 1.33 cubic meters.
A cone is one third of the volume of the cylinder of the same base. Since a cylinder has a volume of pi x radius2 x height, the radius being 5.25m and the height being 3m, the volume of the corresponding cone would be 259.7704425m3.The surface area of the top of the cone is defined as pi x radius x slant height. The slant height, by pythagoras, is 6.046693311m, and so the area of the canvas required to cover the heap would be 99.73029825m2.
25.13m2
A rectangular prism with a length of 11m, width of 8m and height of 3m has a volume of 264m3
Volume of the cylinder = (pi) x (radius of base)2 x (height)V = (3.1416) x (10)2 x 3 = 300(pi) = 942.4778 m3 (rounded)1 m3 = (100 x 100 x 100) cm3 = 1,000,000 cm31 liter = 1,000 cm31 m3 = (1,000,000/1,000) = 1,000 litersVolume of the cylinder = 942,477.8 liters
This is a clever problem. It sounds really complicated, but that's only becauseit's actually two simple problems rolled into one.The two problems are:1). Volume of a rectangular prism2). Volume of a cylinderBefore we get started, let's make sure you remember the formulas for both ofthose volumes:1). Rectangular prism . . . V = (length) x (width) x (height)2). Cylinder . . . Volume = (pi) x (radius)2 x (height)The attack is:-- Figure out the volume of the water that rained onto the roof.-- Realize that the same volume poured into the cylindrical tub.-- Figure out how deep that much water fills the cylinder.At this point, the hard part is done! The problem is as good as solved.-- 1.2 cm of rain falls on the 10m x 5.5m rectangular roof. How much water is sitting on the roof ?Volume = L x W x H = (10m) x (5.5m) x (0.012 m) = 0.66 cubic meter of water-- Now pour that water into the cylinder with 3m diameter. How deep is it ?Volume = (pi) x (radius)2 x (height) .We need to find the height, so solve this formula for the height.Divide each side of equation by (pi) x (radius)2 :Height = Volume / (pi) x (radius)2The volume is the 0.66 m3 that poured off of the roof.The radius is 1/2 of the diameter = 1.5m .So Height = (0.66)/(pi) x (1.5)2 = 0.09337 meter = 9.337 cm.
The volume of a box is calculated by multiplying its length, width, and height. In this case, the box is 3m long, 5m high, and 2m wide. Therefore, the volume of the box would be 3m x 5m x 2m = 30 cubic meters.
Radius: 3/2 = 1.5m