We can approximate the radius of a Bowling ball to be about 26.7", the formula for calculating the volume of a sphere is (4/3)*pi*r^3 ,so the volume of our bowling ball is 79730.12 cubic inches
A bowling ball is essentially a sphere. The formula for the volume of a sphere is 4(pi)r3/3. This will give you the approximate volume of the bowling ball, although I do not know how to calculate for the finger holes. So take the radius of the bowling ball (half the diameter), cube it, multiply by 4 pi (you can approximate pi as 3.14) and divide the whole thing by 3. Example: If the bowling ball is 9 inches across, the radius is 9/2 - 4.5 inches. The volume is 4 * 3.1416 * 4.5*4.5*4.5 /3 = 381.7 cubic inches. Since this is equal to about 6250 cm3, you could verify by measuring the displacement of water by a bowling ball, to see if it displaces 6 liters of water. (Variations are due to ball size and finger holes.)
Most likely the bowling ball. According to the laws of physics, an object with more inertia accelerates slower but is harder to stop. The bowling ball accelerates ...
yes
a bowling ball
I suggest that a candlepin bowling ball cannot have a volume of 48 inches cubed since that is huge. 48 inches cubed = 48"*48"*48" = (48*2.54cm)*(48*2.54cm)*(48*2.54cm) >120*120*120cm3 = 1 728 000 cm3 which is more than 300 times larger than the 5274 cm cubed ball.
Used the equation Density=Mass/Volume to solve this one.
I'll assume the bowling ball is a perfect sphere (with finger holes cut out). If the radius of the ball is r, then its diameter is 2r. The ball fits snugly in the box, so its diameter must be the length of one of the sides of the box. Thus the volume of the box is 8r3. The volume of the ball is 4/3πr3
Ten-pin bowling balls usually weigh from about 6 pounds (around 2800 grams) to 16 pounds (about 7200 grams) There are no bowling balls that weigh 200 grams (though such a ball would be leagal as there is no minimum weight) but if there were, the mass of the ball divided by the volume of the ball gives the density. The volume of a standard bowling ball is about 5500 cubic centimeters (I assumed a circumference of 27 inches and calculated from that) 200 / 5500 = 0.036 g/cm3 Compare to the density of air = 0,0012 g/cm3
Since the lightest tenpin bowling ball is currently 6 pounds and a table tennis ball is not even an ounce, the tenpin bowling ball is heavier.
The answer will depend on what characteristic of the ball is being measured: its radius, volume, mass, weight, shine?
A bowling ball is a ball that is used in the game of bowling, where you roll the ball down an aisle and try to knock down as many pins as you can.
The virtual gravity bowling ball is one of the most highly reactive bowling ball in the world.
The circumference of a bowling ball can not be increased.