If its in the shape of a rectangular block, just multiply length x width x height.
If they are mathematical geometric you can use geometry or calculus.If they are not, but are insoluble, you can immerse them in a suitable fluid and measure the volume of the fluid that is displaced. That method will not work for a large salt crystal, though!If they are mathematical geometric you can use geometry or calculus.If they are not, but are insoluble, you can immerse them in a suitable fluid and measure the volume of the fluid that is displaced. That method will not work for a large salt crystal, though!If they are mathematical geometric you can use geometry or calculus.If they are not, but are insoluble, you can immerse them in a suitable fluid and measure the volume of the fluid that is displaced. That method will not work for a large salt crystal, though!If they are mathematical geometric you can use geometry or calculus.If they are not, but are insoluble, you can immerse them in a suitable fluid and measure the volume of the fluid that is displaced. That method will not work for a large salt crystal, though!
Assuming the first measure is also in metres, the answer is 28.69*10-8 m3= 2.87*10-7 m3 or 0.28 cm3.
No.
The answer depends on the object. If the object is of a regular shape the best option would be to measure its dimensions and use geometry to calculate the volume. If the object is small you may be able to find its volume by fluid displacement using a graduated flask (or similar). You will have to find a fluid that does not interact with the object and which is less dense than the object. Fill a graduated flask with the fluid and record the volume. Gently immerse the object and read off the new volume. The difference between the two volume readings will be the volume of the object. Obviously, you will not be able to use water to find the volume of a sugar cube or salt crystals, nor of a block of most kinds of wood. For moderately large objects, you can use two large containers: for example, a bucket and a big tray. Stand the bucket in the tray and fill the bucket to the top with the inert fluid. Then very gently introduce the object into the bucket, collecting the overflowing fluid in the tray. Measure the amount of fluid in the tray using a measuring cylinder or similar. To improve your accuracy, you must lower the object very gently. You can also use additives to reduce the surface tension of the fluid (liquid soap for water). Finally, if the object is big: for example as big as a house, I give up! Challenge your teacher!
diameter = 6.28 inches => radius = 3.14 inches Then volume = pi*r2*h = pi*3.142*6 = 185.85 cubic inches.
28,69 cm3.
2.9 x 10-7 m -3
2.87x10-7 m3
2,44.10-2 x 1,4.10-3 x 8,4.10-3 = 2,87 mm3
This depends on: volume of water, temperature of water, stirring, crystal dimensions, presence of other substances etc.
If they are mathematical geometric you can use geometry or calculus.If they are not, but are insoluble, you can immerse them in a suitable fluid and measure the volume of the fluid that is displaced. That method will not work for a large salt crystal, though!If they are mathematical geometric you can use geometry or calculus.If they are not, but are insoluble, you can immerse them in a suitable fluid and measure the volume of the fluid that is displaced. That method will not work for a large salt crystal, though!If they are mathematical geometric you can use geometry or calculus.If they are not, but are insoluble, you can immerse them in a suitable fluid and measure the volume of the fluid that is displaced. That method will not work for a large salt crystal, though!If they are mathematical geometric you can use geometry or calculus.If they are not, but are insoluble, you can immerse them in a suitable fluid and measure the volume of the fluid that is displaced. That method will not work for a large salt crystal, though!
Assuming the first measure is also in metres, the answer is 28.69*10-8 m3= 2.87*10-7 m3 or 0.28 cm3.
It depends on the experiment. In one particular experiment, using the technique of measuring volume as a means of counting will work. Think of measuring volume; a tablespoon of sugar or salt. When measuring the volume of it, we are measuring how much space it takes up. This can also be a means of counting because once the molar mass of each element is accounted for, the number of moles (counting!) can be calculated.
The ammonia in the salt crystal garden is mixed with the aluiminum
The crystal is broken.
Ammonia will cause the salt crystal to grow bigger and it will also speed up the process of thhe salt crystal forming.
Yes. Salt is a crystalline substance. The ions in the compound form a crystal lattice.