It is not possible to answer the question since that depends on the density of the item.
Consider 22 g of water and 22 g of lead. The lead will occupy much less volume because it has a much greater density.
To find the number of moles of CO2 in 22g, you first need to calculate the molar mass of CO2 (44.01 g/mol). Then, divide the given mass (22g) by the molar mass to get the number of moles. Therefore, 22g of CO2 is equal to 0.50 moles.
The mass of a single copper atom is incredibly small but can be calculated. In this case, 1.055 x 10^-22g is equal to 1.055 x 10^-25 kg when converted from grams to kilograms.
22g thickness refers to a measurement in gauge of the thickness of material, such as metal. The lower the gauge number, the thicker the material. In this case, 22g thickness would indicate a relatively thin material.
to get the answer just take number of moles you have and multiply it by the molecular mass of the compound which is 22g/mol in lithium oxide's case. 23mol x 22g/mol = 506 g of Li2O
This depends on the temperature and the pressure. At standard temperature and pressure 1 mole will occupy 22.4 L, so multiply... 22.4 x 2.22 = 48.728 L at STP.
The balanced chemical equation for the combustion of methane is CH4 + 2O2 -> CO2 + 2H2O. This means that for every mole of CH4 that reacts, one mole of CO2 is produced. The molar mass of CO2 is about 44g/mol, so 22g CO2 is equivalent to 0.5 moles. Therefore, 0.5 moles of CH4 are required to produce 22g of CO2.
22g, 1 inch
22g = 0.776oz
22g per serving
That is approximately 1/20 of a cup
22 grams is 22,000 milligrams.
Using stoichiometry, we can calculate the molar ratio between calcium carbonate and carbon dioxide. When 20g of calcium carbonate decompose to form 8.8g of carbon dioxide, the molar ratio is 1:1. Therefore, to produce 22g of carbon dioxide, you would need the same mass of calcium carbonate, which is 20g.