0.19635 cubic feet.
The volume of water in a 4-inch diameter, 1-foot section of pipe is 0.6528 gallons of water.
The volume of water in a 1 inch x 100 foot pipe is: 4.08 US gallons.
TO answer this question, you need to know the density and the volume of the piece of steel. For example, "mild steel" weighs .284 pounds per cubic inch. The volume of a 12 inch x 12 inch x 1 inch piece of steel is 12 * 12 * 1 = 144 cubic inches. .284 pounds/inch^3 * 144 inch^3 = 40.896 pounds. So each of these steel tiles will weigh about 41 pounds.
1.03 gallons
41/2
The question as posed is unanswerable. In order to compute the weight of an inch of water, one would have to know the volume, or area the one inch covers. (ie., a square foot of water one inch deep would weigh=X)
The volume of the pipe is 0.2078 gallon per foot of length.I have no idea how much water might be in it.
The weight of one foot of a three-quarter inch diameter steel bar will be approximately 1.42 pounds.
cylinder volume equation: pi*r^2*h r=8in h=12in pi*(8in)^2*12in = 2412.743158 cubic inches.
A 5-inch pipe will hold approximately 0.36 gallons of water per linear foot. This calculation is based on the formula for calculating the volume of a cylinder (V = πr^2h), where the radius (r) is half the diameter of the pipe (2.5 inches) and the height (h) is 1 foot.
Steel is typically 490 lb/cubic foot. There are 1,728 square inches in a cubic foot which means that each cubic inch weighs about .284 pounds (just a bit over a quarter of a pound per square inch).
If you mean a container with a volume of 1 cubic foot, then: 1/4 inch ball = 0.0082 cu. inch weigh of each ball (steel) = 0.0023 pounds approx. 73.6 balls per cubic inch (allowing for spherical interlocking) 1728 cubic inches ( one cubic foot) x 73.6 x 0.0023 = 292 pounds. So a cu. ft. container will hold close to 300 pounds of quarter inch steel balls.