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What is the wavelength of a photon emitted during a transition from ni 6 to nf 3 state in the H atom?
Wiki User
∙ 15y ago
if you know the Rydberg constant this is fairly simple question.
the Rydberg constant is 1.097x107m-1 The equation for is
1 / lambda = 1.097x107m-1 ((1/62) - (1/32))
Then the rest is peanuts.
Wiki User
∙ 15y ago
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What is the energy of a photon emitted with wavelength of 518 nm?
3.84 x 10-19 joules.
Transition A produces light with a wavelength of 400 nm Transition B involves twice as much energy as A What wavelenth light does it produce?
Energy per photon is proportional to frequency. That tells us that it's alsoinversely proportional to wavelength.So if Photon-A has wavelength of 400-nm, then wavelength of Photon-Bwith twice as much energy is 200-nm .
What is the wavelength of the photon emitted when a hydrogen atom goes from the second energy level to the first energy level?
121
What is the energy of a photon emitted with a wave length of 654 nm?
The energy of a photon can be calculated using the equation E = hc/λ, where E is the energy of the photon, h is Planck's constant (6.626 x 10^-34 J*s), c is the speed of light (3.0 x 10^8 m/s), and λ is the wavelength of the photon. Plugging in the values, the energy of a photon emitted with a wavelength of 654 nm (or 6.54 x 10^-7 m) is approximately 3.02 x 10^-19 J.
What is the wavelength and frequency of a photon emitted during a transition from n equals 5 to n equals 2 in hydrogen atom?
Drops to the ground state. Use this formula. Hydrogen has a 1 Z number. Frequency = (3.29 X 1015 Hertz) * Z2 * (1/Nf2 - 1/Ni2) To keep it positive, Frequency = (3.29 X 1015 Hertz) * 12 * (1/22 - 1/02) = 8.23 X 1014 Hertz emitted -------------------------------------
What is the energy of a photon emitted with a wavelength of NM?
4.44 10-19 j
What is the energy of a photon emitted with wavelength of 518 nm?
3.84 x 10-19 joules.
When an electron falls from a higher energy level to a lower energy energy level how is the energy released?
The energy is released as electromagetic energy and each transition in each atom has its own wavelength for the light emitted.
Transition A produces light with a wavelength of 400 nm Transition B involves twice as much energy as A What wavelenth light does it produce?
Energy per photon is proportional to frequency. That tells us that it's alsoinversely proportional to wavelength.So if Photon-A has wavelength of 400-nm, then wavelength of Photon-Bwith twice as much energy is 200-nm .
How do the wavelength and frequency of light from Andromeda seem to changed when viewed from earth?
the wavelength of any reflected or emitted photon or other particle is shortened in the direction of travel.
What is the wavelength of the photon emitted when a hydrogen atom goes from the second energy level to the first energy level?
121
What is the energy of a photon emitted with a wavelength of 92.323 nm?
The energy is 2,5116.10-18 J or 13,429 eV.
When an electron in atom changes energy states a photon is emitted If the photon has a wavelength of 550 nm how did the energy of the electron change?
electron lost 3.6 x 10-19 -barbie=]
How do you find the energy of a photon?
You need to know the photon's frequency or wavelength. If you know the wavelength, divide the speed of light by the photon's wavelength to find the frequency. Once you have the photon's frequency, multiply that by Planck's Konstant. The product is the photon's energy.
He high energy photon emitted by a nucleus during fission and radioactive decay?
gamma ray
What is the energy of a photon emitted with a wave length of 654 nm?
The energy of a photon can be calculated using the equation E = hc/λ, where E is the energy of the photon, h is Planck's constant (6.626 x 10^-34 J*s), c is the speed of light (3.0 x 10^8 m/s), and λ is the wavelength of the photon. Plugging in the values, the energy of a photon emitted with a wavelength of 654 nm (or 6.54 x 10^-7 m) is approximately 3.02 x 10^-19 J.
What is the wavelength and frequency of a photon emitted during a transition from n equals 5 to n equals 2 in hydrogen atom?
Drops to the ground state. Use this formula. Hydrogen has a 1 Z number. Frequency = (3.29 X 1015 Hertz) * Z2 * (1/Nf2 - 1/Ni2) To keep it positive, Frequency = (3.29 X 1015 Hertz) * 12 * (1/22 - 1/02) = 8.23 X 1014 Hertz emitted -------------------------------------
