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The mass and weight of a gallon of sea water depend upon the temperature
and salt concentration in the sea water.
Assume T = 60.0 F and C sub salt = 4.0 mass percent
d = ( 64.0 lbm / ft^3 ) ( 1.0 ft^3 / 7.4805 gal ) = 8.56 lbm / gal
m = ( d ) ( V )
m = ( 8.56 lbm / gal ) ( 1.0 gal ) = 8.56 lbm <-----
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