Perimeter = l + l + w + w, where l is the length and w is the width.
P = 2l + 2w
In this case: 70 = 2(2) + 2w
70 = 4 + 2w
66 = 2w
w = 33So the width of the rectangle is 33 feet.
The perimeter of a rectangle with a length of 8.5 feet and a width of 4.5 feet is 26.
108 feet is the perimeter of a rectangle with a length of 50 feet and a width of 4 feet.
The perimeter is 30 feet for this rectangle.
The width is 8 feet
You are describing a cuboid, not a rectangle. A rectangle has only two diminutions, length and width.
5 feet
If the dimensions of the rectangle are in feet, the perimeter will be in feet as well. The area will be in square feet. The area is length x width. The perimeter is 2 x (length + width) or 2 x length + 2 x width.
20
44
gt
15 feet.
63 feet