1 gigabyte is equivalent to 1024 megabytes. So, 35 gigabytes is equivalent to 35 * 1024 = 35840 megabytes.
35840 MBs - 27 MBs = 35813 MBs or 34.973 gigabytes.
answer is 1903.488 MB Rakesh
361 MB
There are 1024 megabytes in a gigabyte, so you have a total of 5120 megabytes, subtract 594.07 mb, and you get 4525.93 mb, or 4.419853515625 gb.
There are 1024 MB in a GB. So you originally have 5120 MB (1024*5). Subtract how many are used (15.798) and you have 5104.202 MB, or approximately 5104 MB.
1000 MB = 1 GB. The theory is if you have a 10GB drive it is 10,000 MB however you loose some of that capacity due to formating. It can vary on how much you loose or someone else can chime in but for my system with Seagate hard drives I lost about 7% per drive. With that average a 10 GB hard drive is actually 9.3 GB (9,300 MB) after formated. So now you just subtract the 167.67 from that and you will get your answer or 9,132.33 MB or 9.1 GB
361 MB
If you subtract positive twenty-seven from negative sixty-nine, you would get negative forty-two. You simply subtract the 27 from the 69 but leave the negative sign.
if you could divide pie by 8 then subtract to equal 45.6 then times by 1700. Would the answer be doubled by 47. or questioned by a milion megabytes?
The capacity of a card indicates the maximum amount of data that can be stored (less some space for the card's own use).Megapixel (MP) count refers to the maximum resolution of the camera's sensor -- its ability to record detail. The number of images that can be recorded on a card of a given size is only indirectly related to the capacity of the card, which is measured in Kilobytes (KB) or Megabytes (MB), not MP. That will vary according to the image itself, and to the camera's settings.For example: My Pentax K10D, with a 10.1 MP sensor and using a 4 GB card, will record approximately 821 images at the highest resolution (10 MP) and a "Fine" resolution setting. The same camera, with the same sensor and same card, will record 10,000-plus images at the lowest resolution (2 MP) and the "Low" resolution setting. Practically all cameras have this ability to change the resolution settings, and thus the sizes of the image files that are stored on the card.So, you can see that it is only possible to answer your question in very general terms: The higher the capacity of the card, the more images you can store at whatever camera settings. And, as you can see above, even at the highest settings with a high MP count, you can take a lot of pictures!One thing to think about: storage cards can and do fail. It is better to have two 1 GB cards than one 2 GB card, unless you plan to shoot a whole lot of video. That way if one fails, you can keep shooting and worry about retrieving the images off the other card later.
This is a tough question to answer for a couple of reasons. First off: There are a lot of motherboards to choose from and there isn't really 1 out there that is absolutely the best. Intense graphics design requires some of the best hardware you can get and the motherboard is only 1 of many things to decide on. The Video Card, Processor and RAM are probably the most important things you will need to choose. The higher the frequency of the FSB (Front Side Bus) the less likely it will be a bottleneck for your graphics. If you are willing to pay a lot of money for a really nice system I could suggest some kind of dual processor board, a PNY video card, and a lot of fast RAM. A good recourse for motherboards is www.mbreview.com There you will be able to find some excellent reviews on the latest motherboards. Some of my favorite brands are AOpen, Chaintech and MSI. They seem to be very reliable. Asus, Gigabyte and Intel are three very good mb makers. If you're looking for extreme high-end, Gigabyte has a new MB with FOUR x16 slots, taking SLI to a new level. If you are looking at using Vista, it's the video card(s) that need the attention, because available RAM is limited to less than 4MB, so the big factor is to get onboard (unshared) memory on your graphics card -- you don't want shared memory, which is going to subtract from RAM available to the CPU. With Win7, this is less of a problem. If you like AMD, the Gigabyte GA-MA790GP-UD4H looks pretty good on the high end. It has 128mb of "side-port" memory that, as I understand it, is dedicated to graphics. I don't think it's a bit deal but it is a plus.
You will be charged for the data usage based on the 1MB as the base charge. If there is a specific price for using 1MB of data, then they will just subtract the data you've used from the 1MB and charge you accordingly.
The B is usually silent during an MB bond, especially at the end of a certain syllable or word like bomb, comb, tomb, womb, dumb, crumb, limb, climb, lamb, thumb, numb, etc. or if there a BT bond at the end of a certain syllable or word like debt, doubt, etc. When you see an MB or BT bond, the B is not always silent and there's still some cases when the B is pronounced. When the MB and BT bond is at a separate syllable like Cambridge, Cambrian, amber, chamber, slumber, obtain, subtract, subtitle, etc., then that's when the B is still pronounced in these bonds. However, there are some rule-breaker exceptions like "subtle", which the B is silent despite the BT bond is at a separate syllable, not at the end of a certain syllable or word.