b - 4 = 5
Add 4 to both sides: b = 9
Example: Let's say b-8.2, where b is an integer. First step, turn the negative exponent to a positive one, and then use the laws of exponents. b-8.2 = 1/b8.2 = 1/b8+1/5 = 1/[b8b1/5] = 1/b8 * 1/b1/5 = 1/b8 * {1(b4/5)/[(b1/5)(b4/5)]} = 1/b8 * b4/5/b(1/5)+(4/5) = 1/b8 * b4/5/b5/5 = 1/b8 * b4/5/b = b4/5/b8+1 = b4/5/b9
a5+b5 = (a+b) (a4-a3b+a2b2-ab3+b4)
No. It contains relative references only.
b4
Using Excel, the statement in cell C4 would be input as follows: =if(B4>99999,0.07,0.05) However, the case where B4 is in between 99999 and 100000 is not accounted for in the solution (or in the question).
Any even number can be expressed as a multiple of two. If you have 5 even numbers, then we can label them as such: a1 = 2*b1 a2 = 2*b2 a3 = 2*b3 a4 = 2*b4 a5 = 2*b5 Where bn is an arbitrary integer So we therefore have: a1 + a2 + a3 + a4 + a5 = 2*b1 + 2*b2 +2*b3 + 2*b4 + 2*b5 = 2*(b1 + b2 +b3 + b4 + b5) We can then let b1 + b2 +b3 + b4 + b5 = c because our sum of 5 numbers is equal to 2*c, this means that the sum is a multiple of 2, and therefore even. QED.
5 Deg B4 TDC. That was as delivered.
The proper and best way to do it is: =B3+B4 You could also do it in any of the following ways: =SUM(B3:B4) =SUM(B3,B4) =SUM(B3+B4)
c
B4, b4, e3
1
b4-3b3-10b2=0 divided by b2 -> b2-3b-10=0 (if b is not 0) Delta=(-3)x(-3) - 4 x 1 x -10 = 49 b=(3+7)/2 or b=(3-7)/2 b=5 or b =-2 if b=0 the equation also holds then b=0 or b=5 of b=-2