Which transformations could have been used to move the platter to the new location? A. a translation 9 units left and a translation 3 units down B. a reflection across MN and a translation 4 units left C. a reflection across MN and a translation 8 units left D. a rotation 180° clockwise about N and a translation 4 units left
A reflection across the origin transforms a point ((x, y)) to ((-x, -y)). After this reflection, a translation of 3 units to the right and 4 units up shifts the point to ((-x + 3, -y + 4)). Therefore, the combined rule for the transformation is given by the mapping ((x, y) \to (-x + 3, -y + 4)).
6
60 units^3
18 units
The vector sum of (7 units down) + (3 units up) is (4 units down).
(2,1)
For this translation, you need to replace every occurence of "x" with "x-3", and every occurence of "y" with "y+5".
Which transformations could have been used to move the platter to the new location? A. a translation 9 units left and a translation 3 units down B. a reflection across MN and a translation 4 units left C. a reflection across MN and a translation 8 units left D. a rotation 180° clockwise about N and a translation 4 units left
The coordinates are (10, 5).
Y=|x+2|
A reflection across the origin transforms a point ((x, y)) to ((-x, -y)). After this reflection, a translation of 3 units to the right and 4 units up shifts the point to ((-x + 3, -y + 4)). Therefore, the combined rule for the transformation is given by the mapping ((x, y) \to (-x + 3, -y + 4)).
translation
In cartesian coordinates (x, y) = (3, -4)
the translation of 2 is the one that triangle moves by 4 units right and 8 units up
The figure will remain in the same position it started as.
A reflection about the x-axis (in other words, turned upside down) and then moved down three units. So basically, it'll end up as an upside down parabola (not squashed, stretched, or anything) with its vertex (which is a maximum) at (0,-3).