The coordinates are (10, 5).
Given only the coordinates of that point, one can infer that the point is located 10 units to the right of the y-axis and 40 units above the x-axis, on the familiar 2-dimensional Cartesian space.
(-4,-2)
(z,z+2) or (z+2,z)
the translation of 2 is the one that triangle moves by 4 units right and 8 units up
That depends on the direction of the point in reference to the original coordinate. If the new point is 5 units to the right of (1,3), then the point is (6,3). If the point is 5 units left of (1,3), then the point is (-4,3). And so on.
Here's an example: In the coordinate plane, the point is translated to the point . Under the same translation, the points and are translated to and , respectively. What are the coordinates of and ? Any translation sends a point to a point . For the point in the problem, we have the following. So we have . Solving for and , we get and . So the translation is unit to the right and units up. See Figure 1. We can now find and . They come from the same translation: unit to the right and units up. The three points and their translations are shown in Figure 2.
The coordinates of a point two units to the right of the y-axis and three units above the x-axis would be (2,3).
(3,0)
(2,1)
The new coordinates are(3 + the old 'x', 2 + the old 'y')
Given only the coordinates of that point, one can infer that the point is located 10 units to the right of the y-axis and 40 units above the x-axis, on the familiar 2-dimensional Cartesian space.
If you we're at the point (8,-2) and you went 5 units right and 2 units up, you'd be at (13,0).
In cartesian coordinates (x, y) = (3, -4)
The point (x, y) is moved to (x+pi/4, y).
(-4,-2)
(z,z+2) or (z+2,z)
the translation of 2 is the one that triangle moves by 4 units right and 8 units up