117*2 = 234
117*10 = 1170
3*39
write the product of 117 two different ways
1 * 117 and -1 * -117 are two ways.
As a product of its prime factors: 3*3*13 = 117 or as 3^2*13 = 117
The sugar content in the two products is different.
9*13 = 117
They are: 9*13 = 117 and 117/9 = 13
3*39 = 117 9*13 = 117
Well the factors of 117 are: 1, 3, 9, 13, 39, and 117 itself. Therefore: 1x117 = 117 3x39 = 117 9x13 = 117
1 and 117, or 3 and 39, etc
32 x 13 = 117
1 x 117, 3 x 39, 9 x 13 = 117