171 = 171/1 and 109 = 109/1 are fractional representations of the numbers.
109/171 as a fraction means '171 divided into 109' . Two methods. #1 Long division. #2 Calculator ; type in in '109' , 'divide sign', '171', '=' The answer should 'pop up on the screen ' '0.6374269...'. Back to # 1. Long Division is a much is a much more tedious process. Set up division bracket 109.000000 ( 0. Notice the decimal point and the 'string of 'zeroes'. We say ' '171' into '109' will not go. So zero in the answer followed by decimal point. Hence 171 ) 1090.00000 ( 0. Then we we say '171' into '1090' foes '6' times ( 171 x 6 = 126) we then with a remainder of 64. Hence we then track down the next zero so the remainder reads, 1260 . Then we we say '171' into '1260' goes '7' times ( 171 x 7 = 1197) we then with a remainder of 63. 171 ) 1090.0000 = 0.67 proceed in this manner until there is no remainder. NB However, the answer may be an irrational number, in which case the long division never ends
As it is, 85.5 is a mixed number.85.5 = 85 1/2To convert said number into a fraction multiply the whole number (85) by the divisor (2).You will get 170.Add that product to the dividend (1).You will get 171.Finally, place that sum over the original divisor (2).Thus, 85.5 as a fraction is: 171/2
-6.84 as a fraction is -684/100. In simplest terms it is -171/25. As a mixed number it is -6 84/100. In simplest terms, it is - 6 21/25.It is -171/25.
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42.75 in a mixed number is 42 3/4 and in an improper fraction is 171/4.
the mixed number would be 3 57/100but the improper fraction would be 171/100
1.71 Decimal 1 71/100 Mixed Fraction 171/100 Improper(top heavy) fraction.
3.42 = 171/50 or 3 21/50
0.342 = 171/500 as a fraction in its simplest form.
85.5 % of a number equates to 85.5/100 of that number. 85.5/100 = 855/1000 = 171/200 as the fraction in its simplest form.
171/250
Number of neutrons = Atomic mass of an isotope - Atomic number of the element The atomic number of meitnerium is 109. Each isotope of an element has a different number of neutrons.