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Assuming the 2 is meant to be a square this is the form: x2 - 3x2 = -2x2 + 8x + 5
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What is x2 plus 7x equals - 2x2 plus 6 in the form ax2 bx c equals 0?
x2 + 7x = 2x2 + 6 x2 - 2x2 + 7x = 6 -x2 +7x - 6 = 0 or alternatively x2 - 7x + 6 = 0
Can you put the equation x2 plus 4x plus 10 equals 3 in the form ax2 plus bx plus c equals 0?
x^2+4x+7
Is x2-2 equals 0 an quadratic equation?
This is called an incomplete quadratic equation because there is no linear term. aX2 +( bX)+ c = 0 The middle term is not there, but this is quite solvable.
When factoring a trinomial that is in the format ax2 plus bx c the number that is represented by B should be viewed as the?
The general form of a quadratic expression is given as ax2+bx+c where "a" cannot equal zero and "b" is the coefficient of the variable "x" and also the sum of the factors of "c" when "a" is unity. Example: x2+5x+6 = (x+2)(x+3) when factored
Is x2 plus 14x plus 49 a trinomial?
In a word, yes. Any simplified form that has 3 terms is a trinomial, but is often in the form ax2 +bx +c where a,b,c are real numbers.
What is the parent function for a quadratic function?
y = x2 is the parent function, but it can be in the form y = ax2 + bx + c
How can I solve a quadratic equations for x in terms of y?
A quadratic involving x and y is usually in the form 'y = ax2 + bx + c'. This form is y in terms of x, so we must rearrange it. y = ax2 + bx + c y/a = x2 + bx/a + c/a y/a = x2 + bx/a + d + e, where c/a = d + e, e = (b/a)2 y/a - e = x2 + bx/a + d y/a -e = (x + b/a)2 √(y/a - e) = x + b/a √(y/a - e) - b/a = x
What is x2 plus 7x equals - 2x2 plus 6 in the form ax2 bx c equals 0?
x2 + 7x = 2x2 + 6 x2 - 2x2 + 7x = 6 -x2 +7x - 6 = 0 or alternatively x2 - 7x + 6 = 0
Put the equation in the form ax2 plus bx plus c equals 0 x2-3 equals 3x2 plus 8x?
2x^2 + 8x + 3 = 0
Can you put the equation x2 plus 4x plus 10 equals 3 in the form ax2 plus bx plus c equals 0?
x^2+4x+7
Is x2-2 equals 0 an quadratic equation?
This is called an incomplete quadratic equation because there is no linear term. aX2 +( bX)+ c = 0 The middle term is not there, but this is quite solvable.
When factoring a trinomial that is in the format ax2 plus bx c the number that is represented by B should be viewed as the?
The general form of a quadratic expression is given as ax2+bx+c where "a" cannot equal zero and "b" is the coefficient of the variable "x" and also the sum of the factors of "c" when "a" is unity. Example: x2+5x+6 = (x+2)(x+3) when factored
Is x2 plus 14x plus 49 a trinomial?
In a word, yes. Any simplified form that has 3 terms is a trinomial, but is often in the form ax2 +bx +c where a,b,c are real numbers.
Factorize x2 plus bx plus ax plus ab?
x2+bx+ax+ab = x2+ax+bx+ab = x(x+a)+b(x+a) = (x+a)(x+b)
Can you put the equation x2 - 5 -4x2 plus 3x equals 0 in the form ax2 plus bx plus c equals 0?
x2-5-4x2+3x = 0 -3x2+3x-5 = 0 or as 3x2-3x+5 = 0
B2 -4ac in the quadratic equation ax2 plus bx plus c equals 0?
Full equation is (-b +/- sqrt(b2 - 4ac))/2a. Try it with x2 - 2x - 3, where a = 1, b = -2 and c = -3...
Solve a-x2 b-x c0 for x?
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