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A quadratic involving x and y is usually in the form 'y = ax2 + bx + c'. This form is y in terms of x, so we must rearrange it.
y = ax2 + bx + c
y/a = x2 + bx/a + c/a
y/a = x2 + bx/a + d + e, where c/a = d + e, e = (b/a)2
y/a - e = x2 + bx/a + d
y/a -e = (x + b/a)2
√(y/a - e) = x + b/a
√(y/a - e) - b/a = x
What else can I help you with?
What are the solutions to the simultaneous equations of x squared plus xy plus y squared equals 7 and 2x plus y equals 1 showing work?
To solve the system of equations x^2 + xy + y^2 = 7 and 2x + y = 1, we can first solve the second equation for y to get y = 1 - 2x. Substituting this into the first equation yields x^2 + x(1-2x) + (1-2x)^2 = 7. Simplifying this equation gives a quadratic equation in terms of x, which can be solved to find two possible values for x. Substituting these values back into the equation y = 1 - 2x will give the corresponding values for y.
Solve the equation for x plus 37 equals 98?
why will the equations x+14=37 and x-14=37 have different solutions for x
How do you solve for x in the equation x2-2x-2 equals 0?
To solve for x in the equation x2 - 2x - 2 = 0, use the quadratic equation, that is: For 0 = ax2 + bx + c, the roots (values of x) are defined as: x = [-b +/- sqrt(b2 - 4ac) ] / 2a (If that's hard to understand, google "quadratic formula"). It works out to x = 2.73, -0.73.
X squared - 4x - 21?
-17
How do you solve 3x2 x-4 equals 0?
3x2+x-4 = 0 (3x+4)(x-1) = 0 Solutions: x = 1 and x = -4/3 By using the quadratic equation formula.
How do you use a graphing calculator to solve quadratic equations?
Graph the equation then find the x intercepts.
How do you solve a biquadratic equation?
Equations of the form z^4+az^2+a_0 are known as biquadratic equations. They are quartic equations. In general they can be solved by reducing them to a quadratic equation where x=z^2 is the variable. Then you can use the quadratic formula or factor. So plugging in x to the biquadratic giives us x^2+ax+a_0.
How do you find a gradient of a linear equation if you are told that it is a tangent to another quadratic equation?
Solve the two equations simultaneously for x. You will probably need the y value as well.Differentiate the quadratic equation.Find the value of the derivative when you substitute the value for x (from step 1) into the derivative.That is the gradient.Solve the two equations simultaneously for x. You will probably need the y value as well.Differentiate the quadratic equation.Find the value of the derivative when you substitute the value for x (from step 1) into the derivative.That is the gradient.Solve the two equations simultaneously for x. You will probably need the y value as well.Differentiate the quadratic equation.Find the value of the derivative when you substitute the value for x (from step 1) into the derivative.That is the gradient.Solve the two equations simultaneously for x. You will probably need the y value as well.Differentiate the quadratic equation.Find the value of the derivative when you substitute the value for x (from step 1) into the derivative.That is the gradient.
Use the quadratic formula to solve the quadratic equations xx-8x-4 equals 0?
x^2 -8x-4=0 x=[8±√(64+16)]/2 x=(8±4√5)/2 x=4±2√5
What is the graph of a quadratic formula?
In general, quadratic equations have graphs that are parabolas. The quadratic formula tells us how to find the roots of a quadratic equations. If those roots are real, they are the x intercepts of the parabola.
How do you solve quadratic equations by finding square roots?
you use difference of squaresex. X^2-4 can be factored out to (x+2)(x-2)you now have the zeros in your equation much easier
How do you solve the quadratic equation x2-k-x equals 0?
2
How does factoring help solve quadratic equations?
Well, that's one method to solve the quadratic equation. Here is an example (using the symbol "^" for power): solve x^2 - 5x + 6 = 0 Step 1: Convert the equation to a form in which the right side is equal to zero. (Already done in this example.) Step 2: Factor the left side. In this case, (x - 3) (x - 2) = 0 Step 3: Use the fact that if a product is zero, at least one of its factors must be zero. This lets you convert the equation to two equations; x - 3 = 0 OR x - 2 = 0 Step 4: Solve each of the two equations.
What is the quadratic formula used for?
The quadratic formula is used all the time to solve quadratic equations, often when the factors are fractions or decimals but sometimes as the first choice of solving method. The quadratic formula is sometimes faster than completing the square or any other factoring methods. Quadratic formula find: -x-intercept -where the parabola cross the x-axis -roots -solutions
How do you solve a quadratic equation graphically?
The roots of the quadratic equation are the x-intercepts of the curve.
How can you solve quadratic functions by completing the square?
x^2-16x=-15 x^2-16x+(-8)^2=-15+(-8)^2 (x-8)^2=49 (x-8)^2=+-7 8+7=15 8=7=1 The solutions are 15 and 1. You can use the example above to solve quadratic equations by completing the square.
How do you solve x 52 x - 22 37 using the quadratic formula?
With great difficulty because it is not a quadratic equation or even a quadratic expression.
