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Strictly speaking, it is a quadratic equation in x. x2 + x = 6 => x2 + x - 6 = 0 => (x+3)*(x-2) = 0 => x = -3 or x = 2
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X2 plus x-30 equals 0?
x2 + x - 30 = (x + 6)(x - 5)
X2 plus 5x plus 3 equals 9?
x2 + 5x + 3 = 9 x2 + 5x - 6 = 0 (x + 6)(x - 1) = 0 x = -6 or x = 1
X2 plus x-6 equals?
-4
X2 plus 2x plus -6 equals 0?
x2 + 2x -6 = 0 x2 + 2x + 1 = 7 (x + 1)2 = 7 x = -1 ± √7
X2 plus 7x plus 6 equals 0?
(x + 6)(x + 1) = 0 so x = either -1 or -6
X2 plus x-30 equals 0?
x2 + x - 30 = (x + 6)(x - 5)
X2 plus 5x plus 3 equals 9?
x2 + 5x + 3 = 9 x2 + 5x - 6 = 0 (x + 6)(x - 1) = 0 x = -6 or x = 1
X2 plus 7x plus 9 equals 3?
x2 + 7x + 9 = 3 ∴ x2 + 7x + 6 = 0 ∴ (x + 6)(x + 1) = 0 ∴ x ∈ {-6, -1}
X2 plus x-6 equals?
-4
X2 plus 2x plus -6 equals 0?
x2 + 2x -6 = 0 x2 + 2x + 1 = 7 (x + 1)2 = 7 x = -1 ± √7
X2 plus 7x plus 6 equals 0?
(x + 6)(x + 1) = 0 so x = either -1 or -6
52-x2 plus x equals 10?
Given that 52 - x2 + x = 10, then -52 + x2 - x + 10 = x2 - x - 42 = (x - 7)(x + 6) = 0. Therefore, x = 7 or -6.
X2 plus 6x plus 9 equals 81?
x2 + 6x + 9 = 81 x2 + 6x = 72 x2 + 6x - 72 = 0 (x+12)(x-6) = 0 x= -12, 6 (two solutions)
What are the roots of the equation x2-7x plus 6 equals 0?
x2- 7x + 6 = 0 factor, (x-6)(x-1) = 0 x = 6 x = 1
X2 plus 6x-72 equals 0?
(x + 12)(x - 6) = 0 x = 6 or -12
Can you solve x squared plus x minus six equals zero?
x2 + X -6 =0 so X2 + X = 6 so X2 = 6-x so X = square root of (6-x) That's as far as I can get it.
What is one solution of X2 plus X-6 equals 0?
x2+x-6=0 * * * * * Perhaps the solution you are looking for is: x2 + x - 6 = (x - 2)(x + 3) = 0; whence, x = 2 or -3.
