x2+7x+12=0 x2+7x=-12 x+Sqaure Root of 7x= 2(SQ Root Symbol)3
-3
-7x - 2y = -3
7x + 5y 7(3) + 5(2) 21 + 10 = 31
79
x2+7x+12=0 x2+7x=-12 x+Sqaure Root of 7x= 2(SQ Root Symbol)3
The value of x2+7x+10 depends on the value of X. If x=1, then x2+7x+10 = 18 If x=2, then x2+7x+10 = 28 If x=3, then x2+7x+10 = 40 and so forth
x2+7x+3 = 0 Using the quadratic equation formula the solutions are:- x = -6.541381265 or x = -0.4586187349
(x + 3)(x + 4)
x2+7x=-2x2+6 3x2+7x-6=0 (3x-2)(x+3)=0 3x-2=0 or x+3=0 x=2/3 or x=-3
(x+3)(x+4)=x2+7x+12
x2-7x+12 = 0 (x-3)(x-4) = 0x=3,4
(x+3)(x+4) = x2+7x+12
=3x * * * * * The correct answer is: x2 + 7x + 12 = (x + 3)(x + 4).
x2-7x+12 (x-3)(x-4)
x2+7x+12=0usually this means to factor the equation.factored this equation would be...(x+3)(x+4)
x2 +7x = 30 x2 +7x - 30 = 0 (x + 10)(x - 3) = 0 Now: x + 10 = 0 or x - 3 = 0 So: x = -10 or x = 3