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Anonymous
x2 + 7x + 9 = 3
∴ x2 + 7x + 6 = 0
∴ (x + 6)(x + 1) = 0
∴ x ∈ {-6, -1}
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x2+7x+12=0 x2+7x=-12 x+Sqaure Root of 7x= 2(SQ Root Symbol)3
-3
-7x - 2y = -3
7x + 5y 7(3) + 5(2) 21 + 10 = 31
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