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What are the polynomials in x3 plus 8x2 plus 15x?
x(x+3)(x+5)
What is the rational zeros for x3 plus x2-17x plus 15?
x3 + x2 - 17x + 15 = (x - 1)(x - 3)(x + 5). Thus, the zeros are 1, 3, and -5. All three zeros are rational.
What is 8x2 y x3 y2 5y?
Assumption 8x2 = eight times x squared Assumption: x3 is x to the third Assumption: y2 is y squared Answer 40 y to the fourth x to the fifth = 40 y4 x5
Solve x3 plus 7x equals 8x2?
x3 + 7x = 8x2x3 + 7x - 8x2 = 0 [subtract 8x2 from both sides]x(x2 + 7 - 8x) = 0 [factor out x]x(x-1)(x-7) = 0 [factor]Since the product of the three factors x, x-1, and x-7 equals zero, any of the three expressions could equal zero:x = 0x - 1 = 0, x = 1x - 7 = 0, x = 7Therefore, there are three solutions to the equation x3 + 7x = 8x2:x = 0x = 1x = 7Or, in set notation: x = {0,1,7}
X3 - 18x2 plus 17x?
x(x - 17)(x - 1)Factorising x3 - 18x2 + 17x:Common factor x of all terms:x(x2 - 18x + 17)17 = -1 x -17, -1 + -17 = -18:x(x - 1)(x - 17)
What are the polynomials in x3 plus 8x2 plus 15x?
x(x+3)(x+5)
What is the rational zeros for x3 plus x2-17x plus 15?
x3 + x2 - 17x + 15 = (x - 1)(x - 3)(x + 5). Thus, the zeros are 1, 3, and -5. All three zeros are rational.
Completely factor the polynomials for x3 plus 8x2 plus 15x?
x(x+3)(x+5)
How do you factor x3-8x2?
x2(x - 8)
By using the factor theorem find the prime factors of the polynomial x3-x2-17x-15?
(x + 1)(x + 3)(x - 5)
How do you find a cubic equation with integral coefficients that has the roots 2 and 4 plus i?
If it has integral coefficients and 4+i is a root then its conjugate, 4-i must also be a root. So the equation is f(x) = (x-2)*(x-4-i)*(x-4+i) where each factor is x minus a root. Then multiply these out. = (x-2)*(x2 - 8x + 17) = x3 - 2x2 - 8x2 + 16x + 17x - 34 = x3 - 10x2 + 33x - 34
What is -x3 plus 75x-250 divided by x plus 10?
(-x3 + 75x - 250) / (x + 10) = x2 - 10x - 25
What is 8x2 y x3 y2 5y?
Assumption 8x2 = eight times x squared Assumption: x3 is x to the third Assumption: y2 is y squared Answer 40 y to the fourth x to the fifth = 40 y4 x5
Solve x3 plus 7x equals 8x2?
x3 + 7x = 8x2x3 + 7x - 8x2 = 0 [subtract 8x2 from both sides]x(x2 + 7 - 8x) = 0 [factor out x]x(x-1)(x-7) = 0 [factor]Since the product of the three factors x, x-1, and x-7 equals zero, any of the three expressions could equal zero:x = 0x - 1 = 0, x = 1x - 7 = 0, x = 7Therefore, there are three solutions to the equation x3 + 7x = 8x2:x = 0x = 1x = 7Or, in set notation: x = {0,1,7}
What is the quotient and remainder of 4x4 -x3 plus 17x2 plus 11x plus 4 when divided by 4x plus 3?
Dividend: 4x^4 -x^2 +17x^2 +11x +4 Divisor: 4x +3 Quotient: x^3 -x^2 +5x -1 Remainder: 7
What is 17x3?
17x-3 = 14
X3 - 18x2 plus 17x?
x(x - 17)(x - 1)Factorising x3 - 18x2 + 17x:Common factor x of all terms:x(x2 - 18x + 17)17 = -1 x -17, -1 + -17 = -18:x(x - 1)(x - 17)
