x3 + 7x = 8x2
x3 + 7x - 8x2 = 0 [subtract 8x2 from both sides]
x(x2 + 7 - 8x) = 0 [factor out x]
x(x-1)(x-7) = 0 [factor]
Since the product of the three factors x, x-1, and x-7 equals zero, any of the three expressions could equal zero:
x = 0
x - 1 = 0, x = 1
x - 7 = 0, x = 7
Therefore, there are three solutions to the equation x3 + 7x = 8x2:
Or, in set notation: x = {0,1,7}
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7x + 2 = 5,6
Subtract by 7x and divide by 2.
7x = 3x - 12 4x=-12 x=-3
7x+2-2=16-27x = 147x/7 = 14/7x = 2
sin7x-sin6x+sin5x