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x3 + 7x = 8x2

x3 + 7x - 8x2 = 0 [subtract 8x2 from both sides]

x(x2 + 7 - 8x) = 0 [factor out x]

x(x-1)(x-7) = 0 [factor]

Since the product of the three factors x, x-1, and x-7 equals zero, any of the three expressions could equal zero:

x = 0

x - 1 = 0, x = 1

x - 7 = 0, x = 7

Therefore, there are three solutions to the equation x3 + 7x = 8x2:

  1. x = 0
  2. x = 1
  3. x = 7

Or, in set notation: x = {0,1,7}

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14y ago

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