it is only solve-able if "-2-x-3-9-26" is equivelent to something..... Such as: x+2-42=0 ; x=40 Notice that the equation equals Zero
11
18
-18
log x + 2 = log 9 log x - log 9 = -2 log (x/9) = -2 x/9 = 10^(-2) x/9 = 1/10^2 x/9 = 1/100 x= 9/100 x=.09
18 ÷ 9 x 2 = (18 ÷ 9) x 2 = 2 x 2 = 4
x^2 +9 =x^2 -9 9=-9 No solution
3x+9/2=9 3x=9-9/2 3x=9/2 x=9/6 x=3/2
x2-7x-18 (x-9) (x+2) x=9 x=-2 X= either 9 or -2
x+2=9 x=9-2 x=7
log x + 2 = log 9 log x - log 9 = -2 log (x/9) = -2 x/9 = 10^(-2) x/9 = 1/10^2 x/9 = 1/100 x= 9/100 x=.09
18 ÷ 9 x 2 = (18 ÷ 9) x 2 = 2 x 2 = 4
x^4 + 8x^2 - 9 = (x^2 - 1)(x^2 + 9) = (x - 1)(x + 1)(x^2 + 9)
x^2 +9 =x^2 -9 9=-9 No solution
3x+9/2=9 3x=9-9/2 3x=9/2 x=9/6 x=3/2
x+9=xx x+9=x^2 x^2-x-9=0 Quadratic formula: x=[1±√(1+36)]/2 x=(1±√37)/2
log9(x)=2 x=9^2 x=81
36/2=18 18/2=9 9/3=3 36/3=12 12/2=6 6/2=3 36/4=9 9/3=3 36/6=6 6/2=3
x2-7x-18 (x-9) (x+2) x=9 x=-2 X= either 9 or -2
x(9+x)=x^2 + 9x
Factor them. 3 x 3 = 9 2 x 2 x 3 x 3 = 9 2 x 2 x 2 x 2 x 2 x 2 = 64 Combine the factors, eliminating duplicates. 2 x 2 x 2 x 2 x 2 x 2 x 3 x 3 = 576, the LCM