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Equations: x/3 -y/4 = 0 and x/2 +3y/10 = 5.4

Multiply all terms in the 1st equation by 12 and all terms in the 2nd equations by 10

So: 4x -3y = 0 and 5x +3y = 54

Add both equations together: 9x = 54 => x = 6

Solution solved by substitution: x = 6 and y = 8

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Q: What is x over 3 minus y over 4 equals 0 and x over 2 plus 3y over 10 equals 5.4 solved simultaneously?
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