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Q: What is y 56 equals 25?

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Well you can find what it equals in terms of x. If you know that y plus y equals 25 to the power of 25 then you know that 2y=25^25 which means that y=(25^25)/2 - this is a huge number. To find x+y you just add x to what y equals so you get x+(25^25)/2

If by area you mean X*Y it would be -49 (or 49, if you assume area to be positive). (X=7, Y=-7) when X+Y^2=56 and X+Y=0.

4y20 = 500 => y20 = 25 => y = 20√25 = 1.1746 approx Then x = 500 - y = 489.8254 (approx).

y2 + y2 - 56 let's factor it such as = 2y2 - 56 = 2(y2 - 28) = 2[y2 - (√28)2] = 2(y - √28)(y + √28) = 2(y - √4*7)(y + √4*7) = 2(y - 2√7)(y + 2√7)

25% is a quarter so 14 x 4 = 56

Related questions

An equation where y = 81

Well you can find what it equals in terms of x. If you know that y plus y equals 25 to the power of 25 then you know that 2y=25^25 which means that y=(25^25)/2 - this is a huge number. To find x+y you just add x to what y equals so you get x+(25^25)/2

y / 8 = 56 So multiply both sides by 8 to get y = 56 * 8 So y = 448

56

y =x^2-x-56 is the same as y = (x + 7)(x - 8)

y=.25

31

y=(320 x 25 )/ 40 = 200.

y= -25

If by area you mean X*Y it would be -49 (or 49, if you assume area to be positive). (X=7, Y=-7) when X+Y^2=56 and X+Y=0.

x/y = 5/(y^2) and y/x = 5/(x^2). So x/y + y/x = 5/(y^2) + 5/(x^2), which equals 5x^2/(x^2 y^2) + 5y^2/(x^2 y^2) equals 5(x^2 + y^2)/25 equals (x^2 + y^2)/5. x^2 = 25/y^2, so you get (25/y^2 + y^4/y^2)/5 equals ((25 + y^4)/y^2)/25, which shows that your math teacher is on crack. Seriously, I'm not sure that's true.

y = -5