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What is the value of x and y if y plus y equals 25 to the power of 25?
Well you can find what it equals in terms of x. If you know that y plus y equals 25 to the power of 25 then you know that 2y=25^25 which means that y=(25^25)/2 - this is a huge number. To find x+y you just add x to what y equals so you get x+(25^25)/2
What is the area of the region x plus y squared equals 56 when x plus y equals 0?
If by area you mean X*Y it would be -49 (or 49, if you assume area to be positive). (X=7, Y=-7) when X+Y^2=56 and X+Y=0.
4y20 equals 500 and x plus y equals 500?
4y20 = 500 => y20 = 25 => y = 20√25 = 1.1746 approx Then x = 500 - y = 489.8254 (approx).
Y squared plus y squared - 56 equals?
y2 + y2 - 56 let's factor it such as = 2y2 - 56 = 2(y2 - 28) = 2[y2 - (√28)2] = 2(y - √28)(y + √28) = 2(y - √4*7)(y + √4*7) = 2(y - 2√7)(y + 2√7)
What is 25 percent of blank equals 14?
25% is a quarter so 14 x 4 = 56
What is y-56 equals 25?
An equation where y = 81
What is the value of x and y if y plus y equals 25 to the power of 25?
Well you can find what it equals in terms of x. If you know that y plus y equals 25 to the power of 25 then you know that 2y=25^25 which means that y=(25^25)/2 - this is a huge number. To find x+y you just add x to what y equals so you get x+(25^25)/2
What is the solution to y divided 8 equals 56?
y / 8 = 56 So multiply both sides by 8 to get y = 56 * 8 So y = 448
What is -7y equals -63?
56
How do you factor y equals x2-x-56?
y =x^2-x-56 is the same as y = (x + 7)(x - 8)
What does 56 equals a - 25 equal?
31
If y varies inversely as x and y equals 320 when x equals 25 find y when x is 40?
y=(320 x 25 )/ 40 = 200.
What is y plus 7 equals -18?
y= -25
What is the area of the region x plus y squared equals 56 when x plus y equals 0?
If by area you mean X*Y it would be -49 (or 49, if you assume area to be positive). (X=7, Y=-7) when X+Y^2=56 and X+Y=0.
If x squared y squared equals 25 xy equals 5 prove that x over y plus y over x equals 5 somebody HELP?
x/y = 5/(y^2) and y/x = 5/(x^2). So x/y + y/x = 5/(y^2) + 5/(x^2), which equals 5x^2/(x^2 y^2) + 5y^2/(x^2 y^2) equals 5(x^2 + y^2)/25 equals (x^2 + y^2)/5. x^2 = 25/y^2, so you get (25/y^2 + y^4/y^2)/5 equals ((25 + y^4)/y^2)/25, which shows that your math teacher is on crack. Seriously, I'm not sure that's true.
Find an equation of variation where y varies directly as x and y equals 2 when x equals 10 find y when x equals -25?
y = -5
3y plus 5 equals y-25?
3y+5=y-25 2y=-30 y= -15
