Original problem: log2(y-4) + log2y = 2
The first step is applying a log property to the first term which states that logbn + logba = logb(na)
So we can change the left side of the equation to log2[y(y-4)] or log2(y2-4y).
Then we apply another log property which states logbn = a is equivalent to ba = n
So we can change log2(y2-4y) = 2 to the equation 22 = y2-4yor 4 = y2 - 4y
Now we can swing the four around to make the quadratic y2 - 4y - 4 = 0
Unfortunately, whoever assigned you this problem decided to make it more difficult because the expression y2 - 4y - 4 is unfactorable, meaning you have to use the quadratic formula. With it, you should be able to find the two values for y: 2 ± √32/2
You use Plus as a symbol in Maths. Example, 2 Plus 2 equals 4. Or in symbols it would be 2+2=4. __________________________ Plus = + Equals = = (Equals equals =)
no if 1 plus 1 equals 2 then 2 plus 2 equals 4.
No.
2 plus 2 equals 4plus1 equals 5minus 1 equals 4divided by 2 equals 2plus 8 equals 1010 minus 6 equals 4so it all equals to +_____29so its 29 !!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!
2048
143544
7+2+5= 14 35 42
96
144
26
If I am correct, 9 plus 7 equals 112.
Since 2 plus 4 is not 10, the "if" statement is false. Given a false "if", logically, 9 + 2 can equal anything you like.