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It is 8961 - W*int(8961/W)
100015
11
27836/56 gives 497 and 4 as quotient and remainder Dividend- remainder =27836-4 = 27832 which is divisible by 56. So the least no that to be subracted is 4
the least number divisible by 1, 2, 3, 4 & 6 is 12.
It is 8961 - W*int(8961/W)
It is 20 because 5220/180 = 29
9400÷65 gives144 quotient,40 remainder. 65×145 =9425 25 is the least
10056÷23 gives 437 as quotient and 5 as remainder. Dividend-remainder= divisor× quotient so 10056-5=23×437 gives 10051.our question is least no should be added to 10056 which is divisible by 23. Check next possibility 23×438 gives 10074. Now 10056+18= 10074. Therefore 18 is the least number should be added to 10056 to get a number divisible by 23
100015
Dividend-remainder= divisor*quotient 5694/43 give 132 quotient and 18 remainder.now 5694-18 =5676 is exactly divisible by 43. so 18 must be subracted.
what is the least 5- digit number which is exactly divisible by 36
13801-55 = 13746 and 13746/87 = 158
None. The LCM (least common multiple) is the smallest positive whole number exactly divisible by two or more whole numbers.
11
3500/42 give 83 quotient,14 remainder next possibility 42*84 =3528. 28 must be added to 3500 then only it will divisible by 42.now check the dividend 3528 with the following divisor 49,56,63 3528/49=72 divisible 3528/56=63 divisible 3528/63=56 divisible So 3528 is divisible by 42,49,63,56 So 28 must be added 28 is the
None. The LCM (least common multiple) is the smallest positive whole number exactly divisible by two or more wholenumbers.