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The smallest number that can be subtracted from 1294, yielding a result that when divided by 9, 11, and 13 leaves a remainder of 6 is 1. To prove this, run the following snippit of a program

int i;

for (i=1294; i!= 0; i--)

if (i % 9 6) break;

printf("%u", 1294-i);

another way to prove it it to multiply 9 11 and 13, yielding 1287, adding six, yielding 1293, which is one away from 1294.

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Q: What least number must be subtracted from 1294 so that the remainder when divided by 9 11 and 13 will leave in each case the same remainder 6?
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