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To determine the grams of ethylene needed to react with 0.0126 mole of water, you need to use the balanced chemical equation for the reaction between ethylene and water. Once you have the balanced equation, use the molar ratio between ethylene and water to convert moles of water to moles of ethylene. Then, use the molar mass of ethylene to convert moles of ethylene to grams of ethylene.
I can't
63 g of water are needed.
There is an energy problem.
Potassium oxide violently react with water !
To determine the grams of ethylene needed to react with 0.0126 mole of water, you need to use the balanced chemical equation for the reaction between ethylene and water. Once you have the balanced equation, use the molar ratio between ethylene and water to convert moles of water to moles of ethylene. Then, use the molar mass of ethylene to convert moles of ethylene to grams of ethylene.
I can't
63 g of water are needed.
28g Fe
62 grams a+
62 grams a+
Yes very easily , forming the 1-butyne-4-ol or 4-hydroxy-1-butyne.
The answer is 1,25 moles iron(III) oxide.
There is an energy problem.
16.0 g
155.2 g
Potassium oxide violently react with water !