Depending on the size of the object this can be difficult. Use a large volumetric beaker, fill with a certain volume of water. Place the object into the water so that it is totally submerged. The displacement of water caused by the object will give you a new volume of water within the container. The difference in volumes give you the volume of your object.
the water displacement method
Use volume displacement method.
It depends on what the second method is!
Mass divided by Volume = Density. Or use the displacement method for an irregularly shaped object.
It is the displacement method.
Google "Archimedes' Principle" and see if that gives you a clue...
Half fill a graduated glass beaker with water and note the level. Place irregularly shaped object into the beaker. Note the new level. The difference between the two levels is the volume of the object. cw: OK, that method works for objects that don't get wet -- like steel. Tissue paper would not be a good candidate. Also, if the object floats, you have to submerge the object.
Immerse the object completely in a liquid (e.g. water) and measure the volume of liquid displaced.
It is used to find the volume of an irregularly shaped object. An object dropped into a volume of water will displace an equal volume of water.
If the object in question is water proof, and small enough. You can measure the amount of displaced water when it is placed in a tank full of water, this may not work for a lot of things but it can help when attempting to measure some objects.
method usede to figure the volume of an irregular shaped object
When you are trying to find the volume of an irregularly shaped object.