Q: What number am I I have 2 digits which have a sum of 7 both of my digits are less than 5 my tens digit is greater than my ones digit?

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A 6-digit number will ALWAYS be greater than a 5-digit number. Assuming both are positive of course.

73 is the largest 2 digit number that is both prime and has prime numbers for both of its digits.

For now, I'll assume for simplicity that the numbers are positive. The number with the greatest amount of integer digits (before the decimal point, if any) is larger. If both numbers have the same number of integer digits, compare each digit in turn until you find one digit that is different. The number with the largest digit in this place is larger. Examples: 1234 is greater than 430, because it has more digits. 125 is greater than 117, because in the first digit they differ (second position from left), it has the greater digit. 0.007 is greater than 0.0009, because in the third digit to the right of the decimal point (the first digit where they differ), it has the greater digit (7 is greater than 0).

The 2-digit number must be 20, because it is the only 2-digit number whose sum of its two even digits, 2 + 0 = 2, is greater than the product of its two even digits, 2 x 0 = 0. Moreover, 20 is a product of the two consecutive integers 4 and 5.

73 is the largest two-digit number that is prime and has prime numbers for both of its digits.

If x - y > 0, then x is greater than y.The greater positive number is the one further from zero.Which number is greater can be worked out on a digit by digit basis:To compare numbers starting with the highest place value column compare the digits, moving right a place value column until either all digits have been considered or one digit is higher than the other - the number with the higher digit is the greater number. (If a place value column is empty, its digit value is 0).

26.

There are only two smaller 3-digit numbers and both of them have repeated digits.

44? ? ?

5.43 is greater than 5.34. To find this, is to compare the first digits from left to right in both sides of the two given numbers. if they are same, move to the next second digits and on til you find the number that has bigger digit

23

If they have whole numbers before the decimal point, it's easy. The one with the greaterwhole number before the decimal point is the greater number.If neither one has a whole number before the decimal point, then look for the first placeafter the decimal points where their digits are different.If one has more digits than the other, then zeros can be added to the right of the rightmost digit, without changing the value. The number with the greater digit in that place is the greater number.Example: compare .09 and .15 : The first digit that is different is 0 and 1. 1 > 0 so .15 is greater.How about .2 and .23 ? The first digit is 2 in both, .2 doesn't have any more digits, so make it .20, then compare 0 and 3, so .23 is greater.

56

12

11

A positive number is greater than a negative number. If both numbers are positive, the longer number - the one with more digits - is larger. If both have the same number of digits, compare the digits from the left, one at a time until you find one that is different. The one with the larger digit in this last comparison is the larger number.

56

There is a lot of answer for this, but I tell you one. The answer is 6541.

2

Take the question apart, one step at a time. The remainder, when the number is divided by 5, is 4. That means that the ones digit is either 4 or 9. However, you know that both digits are odd, which means it has to be 9. The sum of the digits is 10, so the tens digit has to be 1. Your number is 19.

They are the same because they are both multiplication. They also can be the same if the two digit number times by the one digit number equals a three digit number. They are different because the 3 digits number will obviously produce a higher product.

12, 24 and 36 all qualify...

Since both of those numbers contains four digits, there are no three-digit numbers between them.

35 is the smallest number with ANY quantity of digits that qualifies.

To be an even number then the final digit = 2. The largest single prime digit is 7 (as both 8 and 9 are composite). The greatest even number fulfilling the conditions is 77777772.