To be an even number then the final digit = 2.
The largest single prime digit is 7 (as both 8 and 9 are composite).
The greatest even number fulfilling the conditions is 77777772.
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Find the greatest product of five consecutive digits in the 1000-digit number.7316717653133062491922511967442657474235534919493496983520312774506326239578318016984801869478851843858615607891129494954595017379583319528532088055111254069874715852386305071569329096329522744304355766896648950445244523161731856403098711121722383113622298934233803081353362766142828064444866452387493035890729629049156044077239071381051585930796086670172427121883998797908792274921901699720888093776657273330010533678812202354218097512545405947522435258490771167055601360483958644670632441572215539753697817977846174064955149290862569321978468622482839722413756570560574902614079729686524145351004748216637048440319989000889524345065854122758866688116427171479924442928230863465674813919123162824586178664583591245665294765456828489128831426076900422421902267105562632111110937054421750694165896040807198403850962455444362981230987879927244284909188845801561660979191338754992005240636899125607176060588611646710940507754100225698315520005593572972571636269561882670428252483600823257530420752963450
Its impossible, there are only 5 single digit numbers that are not prime
6 x 7 = 42 (it helps to know the multiplication tables), so the prime factors are 2 x 3 x 7, and the combination is 237
There is no simple formula for that; I suggest you look up the prime numbers in a table of prime numbers, analyzing each prime number in the range 10-99 whether it fulfills this specific criterion.
There are four 2-digit prime numbers that have 4 as one of their digits: 41, 43, 47, and 49. However, 49 is not a prime number because it is divisible by 7. So, the correct answer is three 2-digit prime numbers with 4 as one of their digits.