280.
You break them down to their prime factorization
5 = 5
7 = 7
8 = 2 x 2 x 2
Multiply each one without repeating a number if it appears in two locations- as in it appears in two different numbers factorization (not a problem here since both 5 and 7 are prime)
5 x 7 x 2 x 2 x 2 = 240
It is: 210
No. You can tell this by looking at the last number 5 goes evenly into numbers ending in 0 and 5. Five does not go evenly into 7.
Both 5 and 7 are prime numbers, so the only number that could go into both evenly would be 1.
They will all divide into 280 evenly with no remainder
The number that both 7 and 8 can go into evenly is 56.
the problem is impossible... i know i have the same problem
No, not evenly. These go into 175 evenly: 1, 5, 7, 25, 35, 175.
LCM(5, 7, 8) = 280.
If you are asking whether 7, 3, and 5 will divide evenly into 105, the answer is YES. 7 will go into 105, 15 times evenly 3 will go into 105, 35 times evenly 5 will go into 105, 21 times evenly
in the number 22 the number 2 can go into 22 11 times in the number 35 the number 5 can go into 35 7 times
7 and 31 go into 217 evenly.
The number 7