1.
3
3
3 and 1 will go into both number evenly leaving no remainders.
Just 1 and 3.
If the sum of the digits equals 3, the number is evenly divisible by 3. 2 + 0 + 1 = 3, so 201 is evenly divisible by 3. 1, 3, 67, 201
it is 25
3
1 and 3
3 and 1.
3,5,
It can be divided by 3 and the answer is 41
Not "evenly". It goes in 23 whole times, but then there's 1 left over.