81
Multiplying by 3 in each iteration.
1*3=3
3*3=9
9*3=27
[27*3=81]
Lim(n→0) 27 + 1/n
Next number= 27 X 3 = 81.
105 1st number is 13 = 1 2nd number is 23 = 8 3rd number is 33 = 27 So, 4th number is 43 = 256
81. Each number is the previous number times three. 3 x 27 = 81.
27
27
The next cube number, after 43 = 64 is 53 = 125.
It is '3' to the power(exponent) of 'n-1'. #1 ; 3^(1-1) = 3^(0) = 1 #2 ; 3^(2 -1) = 3^(1) = 3 #3 ; 3^(3-1) = 3^(2) = 9 #4 ; 3^(4-1) = 3^(3) = 27 #5 ; 3^(5-1) = 3^(4) = 81 #6 ; 3^(6-1) = 3^(5) = 243 #n th term ; 3^(n - 1) et seq.,
For each term, multiply the previous by -3. So, 27*-3=-81. -81 is the next term.
-27 You subtract powers of 2 everytime... 1,2,4,8,16
If you just mean what whole number comes after 1 the answer is 2. But if you mean what number comes after 1 I think it's 1.1
If the number is selected at random, then 1/27.