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Q: What is the slope of the line given by the equation y 11x 5?

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11

If you mean y = 11x+2.5 then the slope is 11 and the y intercept is 2.5

If you mean y = 11x then the slope is 11

If you mean: 11x+2y = 34 then y = -10.5x+17 whereas -10.5 is the slope and 17 is the y intercept of a straight line equation

If you mean: y = 11x+1 then the y intercept is 1 and the slope is 11

33y =11x +49 y= 11/33 X +49/33 The slope is coefficient of x. Y = mx+c. m is the slope here. So the slope of above equation is 1/3 --> 0.33

Points: (0, -2) and (20, 42) Slope: 11/5 Equation: 5y = 11x-10 or as y = 2.2x-2.

0.96

11x-4y=32

If: 11x-8y = 32 Then: -8y = -11x+32 And: y = 1.375x-4 in slope-intercept form

Points: (7, 0) and (0, 11) Slope: 0-11/7-0 = -11/7 Equation: y-0 = -11/7(x-7) => 7y = -11x+77 Equation: y-11 = -11/7(x-0) => 7y = -11x+77

-7

If 6x + 10 = 11x , then x=2.

If: -11x+y = 13 Then: y = 11x+13 whereas 11 is the slope and 13 is the y intercept

y = -3/11x +35/11 which can also be expressed in the form of 3x +11y -35 = 0

The equation -30 times -10 plus 11X equals -29. This is a math problem.

Points: (-3, 5) and (-2, -6) Slope: -11 Straight line eqution: y = -11x-28

The general form is 11x - 10y + 19 = 0

9x2+11x-14 = (9x-7)(x+2) when factored with the help of the quadratic equation formula.

There are infinitely many solutions to 11x - 99 = 11(x - 9)

x2+11x+11 = 7x+9 x2+11x-7x+11-9 = 0 x2+4x+2 = 0 The above quadratic equation can be solved by using the quadratic equation formula and it will have two solutions.

-11x - 11

Y=13/11x + 12/11

It is a linear equation in a single variable, x.

That's an invalid equation.

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