5
7 is not the greatest common factor (GCF) of 15, 30, and 35 because 7 does not evenly divide into all three numbers. The GCF is the largest number that can divide all three numbers without leaving a remainder, and in this case, the GCF is actually 5 since 5 divides evenly into all three numbers.
If there is a remainder of 8 when they divide into 113, then they must be factors of 113 - 8 = 105, but not factors of 113, and greater than 8: The factors of 105 are: 1, 3, 5, 7, 15, 21, 35, 105 The factors of 113 are: 1, 113 Thus the 3 numbers which divide 113 with a remainder of 8 are 15, 21, 35, 105 (oops, there are 4 numbers which satisfy the criteria - I never could count...)
They can divide by ten.
Divide the numerator by the denominator. The number above the line is the whole number and the remainder over the divisor is the fraction. For example: 37/5 Divide 37 by 5. The whole number is 7 (5 X 7 is 35). The remainder is 2, so the fraction is 2/5. The mixed number is 7 2/5.
0.2286
1 and 5.
3 with a remainder of 15 or 3.4286
A factor of a number is any number which the original number can divide into evenly. That is to say, can divide into without leaving a remainder, decimal or fraction. The factors of 15 are: 1, 3, 5 and 15 The factors of 20 are: 1, 2, 4, 5, 10 and 20. The factors of 35 are: 1, 5, 7 and 35.
All numbers of that kind: 5, 15, 25, 35, 45, 55, 65... 105, 115... and so on
35 is not the LCM of 3 and 5, 15 is. LCM means Lowest Common Factor. To find the LCM of 3 and 15 you have to list the multiples: 3, 6, 9, 12, 15, 18, 21 etc. 5, 10, 15, 20, 25, etc. The LCM is the least common number in both the lists, which is 15.
35.7143
Because 7 and 5 divide into 35 evenly with no remainder.
7 is not the greatest common factor (GCF) of 15, 30, and 35 because 7 does not evenly divide into all three numbers. The GCF is the largest number that can divide all three numbers without leaving a remainder, and in this case, the GCF is actually 5 since 5 divides evenly into all three numbers.
If there is a remainder of 8 when they divide into 113, then they must be factors of 113 - 8 = 105, but not factors of 113, and greater than 8: The factors of 105 are: 1, 3, 5, 7, 15, 21, 35, 105 The factors of 113 are: 1, 113 Thus the 3 numbers which divide 113 with a remainder of 8 are 15, 21, 35, 105 (oops, there are 4 numbers which satisfy the criteria - I never could count...)
11.4286
Let's find out using the Euclidean method! Divide 35 by 14 and you get 2, remainder 7. Divide 14 (the divisor in the last division problem) by 7 (the last remainder) and you get 2, remainder 0. Because the remainder is zero, the last divisor, 7, is the GCF of 14 and 35. Check. Seven is definitely a factor of both, and if we were to try larger numbers, they would not work: 14 does go into 14, but not into 35; and no number larger than 14 goes into 14.The GCF is 7.
The largest remainder when dividing by 6 is 5. This is true because if the remainder is 6, the 6 would divide into the number again. For example: 35 divided by 6 is 5 remainder 5. 36 divided by 6 cannot be 5 remainder 6 because 6 will divide into 36 again. The answer would be 6.