If there is a remainder of 8 when they divide into 113, then they must be factors of 113 - 8 = 105, but not factors of 113, and greater than 8:
The factors of 105 are: 1, 3, 5, 7, 15, 21, 35, 105
The factors of 113 are: 1, 113
Thus the 3 numbers which divide 113 with a remainder of 8 are 15, 21, 35, 105
(oops, there are 4 numbers which satisfy the criteria - I never could count...)
To find how many times the number 3 is in 113, you can divide 113 by 3. Doing the calculation, 113 divided by 3 equals approximately 37.67. This means that 3 fits into 113 a total of 37 full times, with a remainder.
52 thats your answer :)
When you divide 24 by 7 the remainder is 3.
If you take any four consecutive numbers and divide them by 3, the remainders are as follows: 9/3 = 3 10/3 = 3 remainder 1 11/3 = 3 remainder 2 12/3 = 4 Therefore, the highest remainder you can have by dividing a whole number is 2.
You show your remainder by circling the equal group of numbers and then the remainder stays the same you don't circle it.
To find how many times the number 3 is in 113, you can divide 113 by 3. Doing the calculation, 113 divided by 3 equals approximately 37.67. This means that 3 fits into 113 a total of 37 full times, with a remainder.
ANSWER: 3 and 5225 ÷ 3 = 75 (no remainder)225 ÷ 5 = 45 (no remainder)
If you can divide a number by three without a remainder, the number is said to be divisible by 3.
52 thats your answer :)
When you divide 24 by 7 the remainder is 3.
If you take any four consecutive numbers and divide them by 3, the remainders are as follows: 9/3 = 3 10/3 = 3 remainder 1 11/3 = 3 remainder 2 12/3 = 4 Therefore, the highest remainder you can have by dividing a whole number is 2.
You show your remainder by circling the equal group of numbers and then the remainder stays the same you don't circle it.
87 is one of infinitely many numbers that meet these requirements.
11.3
3 can't divide into anything and leave a remainder of 28. If you divide 43 into 157, the answer is 3, with a remainder of 28.
To find a prime factor of a number, divide by 2 and see if you get no remainder. Then divide by 3, 4, 5, and so on, until one of the numbers you try gets you no remainder. If no such numbers work below the number you chose, it is prime. In the case of the number 9, 2 does not go into 9, but 3 does.
5.375