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If there is a remainder of 8 when they divide into 113, then they must be factors of 113 - 8 = 105, but not factors of 113, and greater than 8:
The factors of 105 are: 1, 3, 5, 7, 15, 21, 35, 105
The factors of 113 are: 1, 113
Thus the 3 numbers which divide 113 with a remainder of 8 are 15, 21, 35, 105
(oops, there are 4 numbers which satisfy the criteria - I never could count...)
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