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301 is one such number.

Q: What number divided by 2 4 5 or 6 has a remainder of 1 but when divided by 7 has no remainder?

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It is an integer which, when divided by 2, leaves a remainder of 1.

3 divided by 2 has a remainder of 1. Which is 1 less than 2.

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solve it with a calculater

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Put the remainder over the number you originally divided by. 15 divided by 7 = 2, remainder 1 = 2 and 1/7

It is not possible, because the number 4 is divisible by 2, and it's remainder is divisible by 2 also, so whatever number works for the "4 with a remainder of 2", will never work for "2 with a remainder of 1.

The LCM of 2, 3, 4 and 5 is 60. Since you need a remainder of 1 just add 1. So the answer is 61. Or any number that is 1 more than a multiple of 60.

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An even number can be divided by 2 evenly. An odd number will have a remainder of 1 when divided by 2.

I think you're wanting a number of two digits, one of which is 3, that when divided by 7 gives a quotient and a remainder of 1 and when that quotient is divided by 2 it gives a remainder of 1: Answer: 36 36 ÷ 7 = 5 r 1 5 ÷ 2 = 2 r 1 If you want the number to be such that if it is divided by 7 the remainder is 1 and if it is divided by 2 the remainder is 1, then: Answer: 43 43 ÷ 7 = 6 r 1 43 ÷ 2 = 21 r 1

85. A number when divided by 238, leaves a remainder 79. What will be the remainder when the number is divided bv 17 ? (1) 8 (2) 9 (3) 10 @) 11

Every 2 digit number, when divided by the number one less than it, will result in a remainder of 1.

179 works until divided by 7 the remainder is 6. 2519 works till 10....

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