It is an integer which, when divided by 2, leaves a remainder of 1.
3 divided by 2 has a remainder of 1. Which is 1 less than 2.
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61,121,181,241,301,361,421,481,541,601,661,721,781,841,901,961,1021,1081,1141,1201, ect
solve it with a calculater
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Put the remainder over the number you originally divided by. 15 divided by 7 = 2, remainder 1 = 2 and 1/7
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No number can satisfy these conditions: To have a remainder of 1 when divided by 6, the number must be odd (as all multiples of 6 are even and an even number plus 1 is odd) To have a remainder of 2 when divided by 8, the number must be even (as all multiples of 8 are even and an even number plus 2 is even) No number is both odd and even. → No number exists that has a remainder of 1 when divided by 6, and 2 when divided by 8.
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